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3 years ago

How many grams are in 9.97 moles of Be(NO3)2? Use two digits past the decimal for all values.

Chemistry

1 answer:

Simora [160]3 years ago

4 0

Answer:

1,869.97 grams of Be(NO3)2

Explanation:

Be(NO3)2 = Be N2 O6

Be=9.012182g/mole

N2=28.0134g/mole

O6=96g/mole

therefore Be(NO3)2 gives you 187.56g in one mole

so 9.97 moles means there is 9.97 times more

9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2

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Lena [83]

Answer:

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Explanation:

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Mice21 [21]

Answer:

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Explanation:

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The law states that 'the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps'.

[2] - 2 × [1] = [3]

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3 years ago

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mash [69]

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