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Yuri [45]
2 years ago
7

How many grams are in 9.97 moles of Be(NO3)2? Use two digits past the decimal for all values.

Chemistry
1 answer:
Simora [160]2 years ago
4 0

Answer:

1,869.97 grams of Be(NO3)2

Explanation:

Be(NO3)2 = Be  N2  O6

Be=9.012182g/mole

N2=28.0134g/mole

O6=96g/mole

therefore Be(NO3)2 gives you 187.56g in one mole

so 9.97 moles means there is 9.97 times more

9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2

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How many moles of Cl in 38.5 mol of CCl2F2?
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Answer:

77 moles

Explanation:

The given chemical compound is CCl2F2 is called Dichlorodifluoromethane. In CCl2F2, we have:

one mole of a Carbon atom.

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Given that one mole of Chlorine = 38.5 moles.

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5 0
2 years ago
Calculate the molarity of the two solutions. The first solution contains 0.550 mol of NaOH in 1.40 L of solution.
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Answer:

0.393 mol/L.

Explanation:

The following data were obtained from the question:

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Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

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Molarity of NaOH = 0.55 / 1.4

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Thus, the molarity of the NaOH solution is 0.393 mol/L.

6 0
3 years ago
The si unit for measuring acceleration is?
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m/s² aka meter per second squared.

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7 0
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