The molarity of H2SO4 is the number of moles in 1 L of solution.
The molarity is 2.0 mol/L
This means that there should be 2 moles in a 1 L solution to make up this molarity.
In this case we need to make up a 5 L solutions with that molarity. Then the amount of moles required are - 2 mol/L x 5 L = 10 mol
A food web is a graphic representation of all possible energy pathways through an ecosystem.
Answer: nucleus
Explanation: the bigger the nucleus there more reactive the atom is
Answer:
0.59 mol O₂
Explanation:
The balanced chemical equation for the decomposition of potassium chlorate (KClO₃) to produce potassium chloride (KCl) and oxygen gas (O₂) is the following:
2 KClO₃ → 2 KCl + 3 O₂
According to the equation, 3 moles of O₂ are produced from 2 moles of KClO ⇒ conversion factor: 3 mol O₂/2 mol KClO₃
Now, we calculate the number of moles of KClO₃ there is in 48.1 g, by dividing the mass into the molecular weight (Mw) of O₂:
Mw(KClO₃) = 39.1 g/mol + 35.4 g/mol + (16 g/mol x 3) = 122.5 g/mol
moles KClO₃ = mass KClO₃/Mw(KClO₃) = 48.1 g/(122.5 g/mol) = 0.3926 mol KClO₃
Finally, we multiply the moles of KClO₃ by the conversion factor to calculate the moles of O₂ produced:
0.3926 mol KClO₃ x 3 mol O₂/2 mol KClO₃ = 0.59 mol O₂
Answer: The density of Uranium Hexafluoride at 60 °C and 745 torr is 0.0127 g/ml
Explanation:
Uranium Hexafluoride is only present as gas at 60 °C and 745 torr.
So, we know PV = nRT, from that
n/V = P/ RT = (745 torr)/(62.36 L-torr/mol*K)(337 K) = 0.0354 mol/L.
Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0127 g/cm³
To learn more about density of Uranium Hexafluoride from the given link
brainly.com/question/17987457
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