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77julia77 [94]
3 years ago
11

Fishermen fishing for spiny lobster are allowed to keep only lobsters with a carapace length of 3.25 inches or longer. (Than car

apace length is measured from the rear edge of the eye socket to the rear edge of the body shell.) Any lobster smaller than 3.25 inches must be returned to the sea. Suppose that lobster carapace lengths have a distribution that is mound shaped and approximately symmetric with a mean of 5.50 inches and a standard deviation of 2.25 inches. Approximately what proportion of lobsters will have to be returned to the sea
Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

16%

Step-by-step explanation:

First we start by solving for the z score

We have the following information

x = 3.25

Standard deviation = sd = 2.25

Mean = 5.50

Z = (x - mean)/sd

z = 3.25 - 5.50/2 25

z = -1.00

If we look this up in the standard normal distribution table,

P(z<-1.00) = 0.1587

Which when approximated gives us

16%

Therefore approximately 16% of lobsters will have to be returned back to the sea.

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Find the slope of this line: y=2x+7
kramer

Answer:

The slope is 2

Step-by-step explanation:

Y = mx+b y = mx+b is the shape of the slope-intercept where m is the slope.

4 0
3 years ago
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What is the final price including tax for the shoes?
Alchen [17]

Answer:

Step-by-step explanation:

$15 × 0.75 × 1.04 = $11.70

$25 × 0.75 × 1.04 = $19.50

$37 × 0.75 × 1.04 = $28.86

$65 × 0.75 × 1.04 = $50.70

3 0
2 years ago
florida received 15 inches of rainfall in 3 months of the year. If the state receive 4.25 each month until the end of the year,
kherson [118]
Since there are 12 months in there year and there have already been 3 months there are 9 left

we need to multiply 4.25 by 9 and then add the first 15 inchess

4.25 times 9 = 38.25+15 = 53.25

Florida will recieve 53.25 inches of rain

I hope I've helped!

3 0
3 years ago
Can an expert help me out with this please.step by step explanation..Ill give brainless and points​
GenaCL600 [577]
5/35 so 1/7 as a decimal this is .143. This is because it says D OR F which means add them and divide by 35. So your answer is 0.143
6 0
3 years ago
Skipping Lunch A nutritionist wishes to determine, within 3%, the true proportion of adults who do not eat any lunch. If he wish
mixas84 [53]

Answer:

A sample of at least 545 adults is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = 0.15

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.  

If he wishes to be 95% confident that his estimate contains the population proportion, how large a sample will be necessary?

We need a sample of at least n.

n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.03}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.03})^{2}

n = 544.23

Rounding up

A sample of at least 545 adults is needed.

6 0
3 years ago
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