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77julia77 [94]
3 years ago
11

Fishermen fishing for spiny lobster are allowed to keep only lobsters with a carapace length of 3.25 inches or longer. (Than car

apace length is measured from the rear edge of the eye socket to the rear edge of the body shell.) Any lobster smaller than 3.25 inches must be returned to the sea. Suppose that lobster carapace lengths have a distribution that is mound shaped and approximately symmetric with a mean of 5.50 inches and a standard deviation of 2.25 inches. Approximately what proportion of lobsters will have to be returned to the sea
Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

16%

Step-by-step explanation:

First we start by solving for the z score

We have the following information

x = 3.25

Standard deviation = sd = 2.25

Mean = 5.50

Z = (x - mean)/sd

z = 3.25 - 5.50/2 25

z = -1.00

If we look this up in the standard normal distribution table,

P(z<-1.00) = 0.1587

Which when approximated gives us

16%

Therefore approximately 16% of lobsters will have to be returned back to the sea.

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To get the reference angle π/6 for the given angles we will check each angle given in the options.
A. 8π/6
Since 8π/6 means 240° which lies in 3rd quadrant. Therefore reference angle of 240°= 240-180 = 60° or π/3
B. 13π/6
13π/6 means 390° which lies in first quadrant.
Therefore reference angle = 390-360 = 30° or π/6
C. 3π/6
Since 3π/6 means 90° therefore reference angle of 90° is the same as 90°.
Or the reference angle is = π/2
D. 5π/6
5π/6 means angle is 150° which lies in second quadrant therefore reference angle of 150° = 180-150 = 30° or π/6
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2 years ago
Help.this question ha sbeen egttin on my nerves for days
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Answer: 8y4+25y3+60y2+10y+7

Step-by-step explanation:

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<u>Step-by-step explanation:</u>

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Recalling the rules for a horizontal asymptote:

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2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

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