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Vsevolod [243]
3 years ago
9

2(1 + 5x) = 5(2x – 1)

Mathematics
2 answers:
LuckyWell [14K]3 years ago
4 0
<span><span>2<span>(<span>1+<span>5x</span></span>)</span></span>=<span>5<span>(<span><span>2x</span>−1</span>)</span></span></span>

Step 1: Simplify both sides of the equation.<span><span>2<span>(<span>1+<span>5x</span></span>)</span></span>=<span>5<span>(<span><span>2x</span>−1</span>)</span></span></span><span><span><span><span>(2)</span><span>(1)</span></span>+<span><span>(2)</span><span>(<span>5x</span>)</span></span></span>=<span><span><span>(5)</span><span>(<span>2x</span>)</span></span>+<span><span>(5)</span><span>(<span>−1</span>)</span></span></span></span>(Distribute)<span><span>2+<span>10x</span></span>=<span><span><span>10x</span>+</span>−5</span></span><span><span><span>10x</span>+2</span>=<span><span>10x</span>−5</span></span>

Step 2: Subtract 10x from both sides.<span><span><span><span>10x</span>+2</span>−<span>10x</span></span>=<span><span><span>10x</span>−5</span>−<span>10x</span></span></span><span>2=<span>−5</span></span>

Step 3: Subtract 2 from both sides.<span><span>2−2</span>=<span><span>−5</span>−2</span></span><span>0=<span>−7</span></span><span>
</span>
mars1129 [50]3 years ago
3 0
2+10x=10x-5
transpose
2+5=10x-10x
7=0
dear student this question does not make sense rewrite or send a picture of your question
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3 years ago
Find the sum of QR<br> 4x+33
12345 [234]

Answer:

Step-by-step explanation:

Simplifying

4x + 5 = 33

Reorder the terms:

5 + 4x = 33

Solving

5 + 4x = 33

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + 4x = 33 + -5

Combine like terms: 5 + -5 = 0

0 + 4x = 33 + -5

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Combine like terms: 33 + -5 = 28

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4 0
2 years ago
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AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is (\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

Read more on equations here: brainly.com/question/13170908

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5 0
2 years ago
Denise bought 116 ounces of beans for a bean dip. She bought both 15-ounce cans and 28-ounce cans, and the total number of cans
Valentin [98]
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that would be ur system of equations

7 0
3 years ago
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s344n2d4d5 [400]
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x = 190/5
x = 38 <==
3 0
3 years ago
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