<span>4(c+2)= -28
Use distributive property
4c+8=-28
Subtract 8 from both sides
4c=-36
Divide 4 on both sides
Final Answer: c=-9</span>
Answer:
<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>
Step-by-step explanation:
To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.
at x = 0;
f(0) = 16 + 2(0) − 0²
f(0) = 16
at the other end point i.e at x = 5;
f(5) = 16 + 2(5) − 5²
f(5) = 16 + 10-25
f(5)= 26-25
f(5) = 1
The absolute minimum value is 1 and occurs at x = 5
The absolute maximum value is 16 and occurs at x = 0
Answer:
Its C but the way I got is too small so I cant really give explanation
When factoring, it's easier to "pick out" the GCF first because it makes it simpler to factor even further. Otherwise, you will be troubled with lots of numbers and variables, so it will just get confusing.
Complete question :
It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
Answer:
0.929 ; 0.306
Step-by-step explanation:
Using the information:
P(stock) = P(s) = 28% = 0.28
P(fixed income) = P(f) = 0.85
P(stock and fixed income) = p(SnF) = 26%
a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.
P(F|S) = p(FnS) / p(s)
= 0.26 / 0.28
= 0.9285
= 0.929
(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
P(s|f) = p(SnF) / p(f)
P(S|F) = 0.26 / 0.85 = 0.3058823
P(S¦F) = 0.306 (to 3 decimal places)
