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adelina 88 [10]
3 years ago
6

Select the coordinates of two points that are on the line x=5

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
You can choose the coordinates of any two points on the vertical line where x=5.
So for the coordinates, you need a y value for both. Since the points have to be on that line, you already know that the x value has to be 5.
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Equivalent ratios of 7/6
Monica [59]
- 14/12
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6 0
3 years ago
Read 2 more answers
Evaluate \dfrac{e}{4}+2f-3 4e +2f−3 when e=12e=12 and f=\dfrac12f= 21<br> ​
dusya [7]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5


Step-by-step explanation:


7 0
4 years ago
Rick and Betty are going to Virginia. It is an 8 hour trip. Rick gets. 50 mile head start and drives at a rate of 55 mph. Betty
maw [93]

The equations y=55x+50 and y=65x represents Rick's and Betty's trip.

Step-by-step explanation:

Given,

Head start of Rick = 50 miles

Speed of Rick = 55 mph

Let,

x be the number of hours

y be the total miles

Distance covered by Rick in x hours = Speed * Time + Head start

y = 55x + 50

Speed of Betty = 65 mph

Total miles = Speed*Time

y=65x

The equations y=55x+50 and y=65x represents Rick's and Betty's trip.

Keywords: variable, addition

Learn more about variables at:

  • brainly.com/question/10525991
  • brainly.com/question/10534381

#LearnwithBrainly

7 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
An equation is shown below: 3(2x − 7) = 9
Katen [24]

Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

so your 1 solution is x = - 1/7

3 0
2 years ago
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