Answer:
75.02 ft
Step-by-step explanation:
Split the problem into 2 different part. The bottom part of the tree is 5 feet because that's where your eye levels are, so you just have to solve the top part of the tree.
The top part of the tree is solved by finding the height of the triangle. If you remember SohCahToa, the opposite side of the angle is solved using tangent.
tan(angle) = opposite/adjacent
tan(35) = x/100, x is just the unknown height of the tree.
multiply 100 on both side to get x by itself.
x = 100tan(35)
x = 70.02
add that top height of the tree(70.02ft) with the bottom height of the tree(5ft).
70.02+5 = 75.02 ft
Answer:
x=27
Step-by-step explanation:
please give brainly
70a + 55b = 905
a + b = 14
55a + 55b = 770
(70a-55a) + (55b-55b) = 905 - 770
15a = 135
a = 9
a + b = 14
9 + b = 14
b = 5
Answer:
Option C
Step-by-step explanation:
Point diagrams show the frequency of occurrence of a series of events after a certain number of trials. In this case, the trials were 100. During each trial it would have been possible to have proportions of {0.24, 0.25, 0.26, 0.27, 0.28 ..... 0.56}
The events with the highest probability of occurrence are those with the highest number of points in the diagram.
Note that the distribution of the points resembles a bell, with a peak (greater clustering of points) between 0.35 and 0.41.
This indicates that it is more likely that the proportion of employees who go to work in bicycles will be between 0.35 and 0.41.
Then the diagram seems to indicate that a proportion less than 0.30 or greater than 0.45 is unlikely (they have less number of points)
Based on this analysis, it can be concluded that the correct option is c)
c) It is plausible that 40% of the population rides a bike to work because the data shows that a sample proportion of 29% is unlikely.
1) Call x the sample mean = 3.56
2) Call s the sample standard deviation = 0.2
3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:
x +/- Z(0.5) s/√n
Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.
Z(0.5) = 0.3085
Then the inteval is
x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
