What is the value of 11−3m, when m = 2?

The original scale factor for a scale drawing of a house plan is 1/80, and the length of the original scale drawing is 12 inches

Leviafan [203]

Answer:3

Step-by-step explanation : because i division

6 0

3 years ago

The cost of one pound of peanuts is 60% of the cost of one pound of cashews. If one pound of cashews costs $2, what is the cost

Sophie [7]

Based on the given problem above, this would appear that,
one pound of peanuts = 0.60*2 = $1.2
one pound of cashews = $2
Therefore, the cost of one pound of peanuts is $1.2.
The total cost of two pounds of peanuts and one pound of cashews would be this: 1.2 + 1.2 + 2 = $4.4
Hope this answers your question.

8 0

3 years ago

Geometry: CC 2015 > Chapter 2: Chapter 2 Test >

tankabanditka [31]

Answer:

The area of ABCF is 2 and 2 × AB = 4

The statement proves that the conjecture is false

Step-by-step explanation:

A conjecture is a proposition or conclusion that is presumed to be true or correct but which is based on incomplete details or information

Given the length of the sides of rectangle ABDE, we have;

Length AB = 2 units

Length DE = 2 units

The area of ABDE = 2 × 2 = 4 unit²

Therefore, the area of the rectangle ABDE is equal to 2 × the length of either AB or DE

However, the are of rectangle ABCF = 2 × 1 = 2 unit²

While the area of rectangle 2 × the length of side AB = 2 × 2 = 4 unit², which is not equal to the number of square units in the area of the rectangle.

Therefore;

The area of ABCF is 2 and 2 × AB = 4

The statement (above) proves that the conjecture is false.

7 0

3 years ago

What is the simplest form of this expression –x3(3x+1)-2x4?

Orlov [11]

Answer:

x^4+x^3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele

kow [346]

Answer:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

Step-by-step explanation:

1) Data given and notation

$\bar X=23500$ represent the sample mean

$s=3900$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2000$

Alternative hypothesis: $\mu > 2000$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since is a one-side upper test the p value would be:

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

8 0

3 years ago