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2 years ago

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The expression 5n+2 can be used to find the total cost in dollars of bowling where n us is the number of games bowled and 2 repr

esents the cost of shoe rental. How much will it cost Vincent to bowl 3 games ?

1 answer:

sukhopar [10]2 years ago

8 0

Plug in the known variables.

5n + 2 n = number of games bowled

5(3) + 2 = 15 + 2 = 17

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Step-by-step explanation:

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3 years ago

Dimetri says that a function that is made of terms where the variables is raised only to an odd power will be an odd function.Do

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Here we want to study the relation between the exponents in a polynomial function and the "odd" property of functions.

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We start by defining an odd function as a function such that:

f(-x) = -f(x).

Now, let's see a simple function with only odd exponents.

f(x) = a*x (the exponent is 1, so it is odd).

if we evaluate this in x = 1, we get:

f(1) = a

If we evaluate this in x = -1, we get:

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Then this is odd.

Now let's see a more general case and why Dimetri is correct.

For the rule of signs, when we multiply 2 negative numbers, the <u>product is positive.</u>

So always that we have an even exponent on a negative number, the outcome will be positive.

This does not happen for odd exponents, because we can't separate all the products in groups of 2, thus if we take the <u>odd exponent of a negative number, the outcome is negative</u>.

Then for functions with only odd exponents, the <u>outcome for evaluating the function in a given input is exactly the opposite of evaluating the same function with the opposite input</u>.

This means that the function is odd.

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If you want to learn more, you can read:

brainly.com/question/15775372

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2 years ago

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Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

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z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

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95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

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The upper limit of this interval is:

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The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

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3 years ago