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kkurt [141]
3 years ago
8

Which of the following sequences of transformation is used to obtain figure A’B’C’D’ from ABCD?

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

Most likely (B)

Step-by-step explanation:

Points of ABCD:

A (3,1)

B (3,4)

C (5,5)

D (5,2)

The algebraic rule for reflecting across the y axis:

(x,y) ---> (-x, y)

Points of ABCD after being reflected: (shown by figure 2)

A (-3, 1)

B (-3, 4)

C (-5, 5)

D (-5, 2)

Then, the figure got translated two units to the left, resulting in figure F in the picture, and A’B’C’D’ in the question.

Points of ABCD after being translated by (x-2, y) : (shown by figure F)

A (-5, 1)

B (-5, 4)

C (-7, 5)

D (-7, 2)

This should be the coordinates of A’B’C’D’.

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Find the first three terms of the sequence with nth term 3n-2​
kykrilka [37]

Answer:

To find out the first three terms of 3n - 2 substitute 1 ,2 and 3 into the equation.

so the three terms a

 3(1)-2=1

3(2)-2=6-2=4

3(3)-2=9-2=7

As you can see the sequence goes up in 1,4 and 7.To find out the 10th term you also substitute 10 into the equation so 3(9)-2=18-2=16

so 16 is the tenth term

Hope this helped!

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3 years ago
Algebraically show that each of the given combinations are equivalent to the given functions.
BlackZzzverrR [31]

Answer:

Yes they ate Equivalent

Step-by-step explanation:

Given the expression

h(x) = - 3x – 1;j(x) = – 7x + 11 ; k(x) = 21.22 – 262 – 11

H(x)•j(x) = (-3x-1)(-7x+11)

H(x)•j(x) = (-3x)(-7x)-3x(11)-1(-7x)(-1)(11)

H(x)•j(x) = 21x²-33x+7x-11

H(x)•j(x) = 21x²-26x-11

This shows that H(x)•j(x) = k(x)

6 0
2 years ago
Whats 834×5 plz tell me
amm1812
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5 0
3 years ago
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Line segment TV is a midsegment of ∆QRS. What is the value of n in the triangle pictured?
Elis [28]

Answer:

D. 3.2

Step-by-step explanation:

Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.

Based on this theorem, we have: TV = ½(RS)

TV = 3n - 2

RS = n + 12

Substitute

3n - 2 = ½(n + 12)

Multiply both sides by 2

2(3n - 2) = (n + 12)

6n - 4 = n + 12

Collect like terms

6n - n = 4 + 12

5n = 16

Divide both sides by 5

5n/5 = 16/5

n = 3.2

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3 years ago
Use a proportion to solve the problem. Round to the nearest tenth as needed. A building casts a shadow 36 m long. At the same ti
Ksenya-84 [330]
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