Which of the following sequences of transformation is used to obtain figure A’B’C’D’ from ABCD?
1 answer:
Answer:
Most likely (B)
Step-by-step explanation:
Points of ABCD:
A (3,1)
B (3,4)
C (5,5)
D (5,2)
The algebraic rule for reflecting across the y axis:
(x,y) ---> (-x, y)
Points of ABCD after being reflected: (shown by figure 2)
A (-3, 1)
B (-3, 4)
C (-5, 5)
D (-5, 2)
Then, the figure got translated two units to the left, resulting in figure F in the picture, and A’B’C’D’ in the question.
Points of ABCD after being translated by (x-2, y) : (shown by figure F)
A (-5, 1)
B (-5, 4)
C (-7, 5)
D (-7, 2)
This should be the coordinates of A’B’C’D’.
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Answer:
<em> (a). ∠UXV, ∠XVY ; (b). UV = 8 m .</em>
Step-by-step explanation:
Assuming we're dealing with , which is the same as writing (x+2)/(-5) < 4, then the answer is choice C.
We multiply both sides by -5 and this will flip the inequality sign.
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Multiplying or dividing both sides by a negative number flips the inequality sign.
An example would be saying -2x < 10 leads to x > -5
What we can do is divide both sides by -2 and flip the inequality sign, or we could follow the steps shown below
- -2x < 10
- 0 < 10+2x ... adding 2x to both sides
- -10 < 2x ... subtracting 10 from both sides; this is one way to see why the sign flip happens
- 2x > -10
- x > -10/2 ..... dividing both sides by 2
- x > -5