![7002 \div 52 \\ \\ 134 \ R34 \\ \\ Answer: \fbox {134.6538} \ or \ \fbox {134 R34}](https://tex.z-dn.net/?f=7002%20%5Cdiv%2052%20%5C%5C%20%5C%5C%20134%20%5C%20R34%20%5C%5C%20%5C%5C%20Answer%3A%20%5Cfbox%20%7B134.6538%7D%20%5C%20or%20%5C%20%5Cfbox%20%7B134%20R34%7D)
This problem can be done by using long division. Using long division via online is quite hard.
I don’t understand this language! sorry..
Answer:
21,35
Step-by-step explanation:
[9tan(θ) * 9cot(θ)] / 9sec(θ)
First cancel out the 9's:
tan(θ)cot(θ)/sec(θ)
Recall the following trig identities:
tan = sin/cos
cot = cos/sin
sec = 1/cos
Thus, we can rewrite the expression as:
[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))
In the numerator, the sine's and cosine's cancel each other out:
1 / (1/cos(θ))
which we can rewrite as cos(θ).
Answer: C
Step-by-step explanation: