Answer:
7/ (3a-1)
Step-by-step explanation:
3a^2 -13a +4 28+7a
------------------ * --------------------
9a^2 -6a+1 a^2 -16
Factor
(3a-1)(a-4) 7(4+a)
------------------ * --------------------
(3a-1) (3a-1) (a-4)(a+4)
Cancel like terms
1 7
------------------ * --------------------
(3a-1) 1
Leaving
7/ (3a-1)
Answer:
p=-7
Step-by-step explanation:
5p=-35
Divide both sides by 5
5p/5 =-35/5
therefore p=-7
The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80).
Note that the number of defectives in the inventory is fixed, i.e., we are not told that there
is 1
8 probability that a modem in the inventory is defective, but rather that exactly 1
8
of
all modems are defective. The probability that exactly two modems in a random sample
of five are defective is = 0.102
The answer is 122/495. Hope this helps!
3 4/5 because if 5 only goes into 19 3 times and then there is 4/5 left
