Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
 
        
             
        
        
        
Sorry I can't solve it.
Firstly, the equation is wrong. It is supposed to be <span>81 ≠ </span><span>30.25
Second of all, this is the best I got </span>81= <span><span>−<span>76 <span>(<span>cos<span>(r) </span></span></span></span></span>+ <span>106.25</span></span>
        
             
        
        
        
Answer:
The auditing book is not accurate
Step-by-step explanation:
25($12.5)+50($8)+125($10)+= $1,925
$312.5 + $400 + $1,250 = $1,925
$1,962.5 not= to $1,925
 
        
             
        
        
        
Answer:
54
Step-by-step explanation:
8(11 - 3) - 2(4 + 1)
11 - 3 = 8
4 + 1 = 5
8(5) - 2(5)
8 * 5 = 64
2 * 5 = 10
64 - 10 = 54