If we were to foil
after experieence
we know
ax²+bx+c=0
and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are
b=(bc+ad)
so
in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9
b=9
or you could just expand it
The end behavior of the function y = x² is given as follows:
f(x) -> ∞ as x -> - ∞; f(x) -> ∞ as x -> - ∞.
<h3>How to identify the end behavior of a function?</h3>
The end behavior of a function is given by the limit of f(x) when x goes to both negative and positive infinity.
In this problem, the function is:
y = x².
When x goes to negative infinity, the limit is:
lim x -> - ∞ f(x) = (-∞)² = ∞.
Meaning that the function is increasing at the left corner of it's graph.
When x goes to positive infinity, the limit is:
lim x -> ∞ f(x) = (∞)² = ∞.
Meaning that the function is also increasing at the right corner of it's graph.
Thus the last option is the correct option regarding the end behavior of the function.
<h3>Missing information</h3>
We suppose that the function is y = x².
More can be learned about the end behavior of a function at brainly.com/question/24248193
#SPJ1
Answer:
84 ounces of pure gold
Step-by-step explanation:
Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy that is 75% gold?
Pure gold = 100% gold
Let the number of ounces of pure gold = x
Hence, we have the equation
40% × 60 ounces + 100%× x ounces = 75%(60 + x)ounces
= 0.4 × 60 + 1x = 0.75(60 + x)
= 24 + x = 45 + 0.75x
Collect like terms
x - 0.75x = 45 - 24
0.25x = 21
x = 21/0.25
x = 84 ounces
Therefore, we need 84 ounces of pure gold
Answer:
338,000
Step-by-step explanation:
202800 is to 338000 like 60% is to 100%
hope that helps lol (did it with my mouse so looks awful)
You will have a better chance of winning because your chance before you opened the first door was 1/3 (since there was 3 doors) but now, you have 2 doors left, so it is a 50% chance that you will win.
