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yulyashka [42]
3 years ago
8

6 cm equals how many mm?​

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

it's 60 mm

Step-by-step explanation:

hope this is useful! have a wonderful day and God Bless you !!!

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Use the double bar graph below to answer the following question.
natali 33 [55]

Answer:

the population would be 1,200,000 of San Diego in 2000

8 0
3 years ago
Which angle measures would make a triangle with three equal side lengths
Verizon [17]

Answer:

60

Step-by-step explanation:

If each side length must be identical, the same must be true for angles. If all the angles added are 180, divide 180 by 3 to get 60.

4 0
4 years ago
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If the price is increasing at a rate of 2 dollars per month when the price is 10 dollars, find the rate of change of the demand.
densk [106]

Answer:

The demand reduces by $7.12 per month

<em></em>

Step-by-step explanation:

Given

p\to price

x \to demand

2x^2+5xp+50p^2=24800.

p =10; \frac{dp}{dt} = 2

Required

Determine the rate of change of demand

We have:

2x^2+5xp+50p^2=24800.

Differentiate with respect to time

4x\frac{dx}{dt} + 5x\frac{dp}{dt} + 5p\frac{dx}{dt} + 100p\frac{dp}{dt} = 0

Collect like terms

4x\frac{dx}{dt} + 5p\frac{dx}{dt} = -5x\frac{dp}{dt}  - 100p\frac{dp}{dt}

Factorize

\frac{dx}{dt}(4x + 5p) = -5(x  + 20p)\frac{dp}{dt}

Solve for dx/dt

\frac{dx}{dt} = -\frac{5(x  + 20p)}{4x + 5p}\cdot \frac{dp}{dt}

Given that: 2x^2+5xp+50p^2=24800. and p = 10

Solve for x

2x^2 + 5x * 10 + 50 * 10^2 = 24800

2x^2 + 50x + 5000 = 24800

Equate to 0

2x^2 + 50x + 5000 - 24800 =0

2x^2 + 50x -19800 =0

Using a quadratic calculator, we have:

x \approx -113\ and\ x\approx88

Demand must be greater than 0;

So: x=88

So, we have: x=88; p =10; \frac{dp}{dt} = 2

The rate of change of demand is:

\frac{dx}{dt} = -\frac{5(88  + 20*10)}{4*88 + 5*10} * 2

\frac{dx}{dt} = -\frac{5(288)}{402} * 2

\frac{dx}{dt} = -\frac{2880}{402}

\frac{dx}{dt} \approx -7.16

<em>This implies that the demand reduces by $7.12 per month</em>

8 0
3 years ago
please help me figure out how to determine the range of the following graph (the line y=5 is a horizontal asymptote)
prisoha [69]

we are given the graph of the function and we are interested in finding the range of the function. Recall that the range of a graph is simply the set of values on the y axis, for which there is a point on the graph that has that y coordinate.

One easy way to spot this set, is by taking any point on the graph and then drawing a horizontal line. Wherever the line crosses the y axis, that point is included in the range.

From the graph, we can see that no part of the graph has values with y coordinate less than 5. That is, any number less than 5 in the y coordinate would indicate that there is no point on the graph at that "height". So every number less than 5 is excluded from the range.

We are also told that line y=5 is a horizontal asymptote. This means that despite the graph is really close to the line y=5 (and it keeps getting closer and closer as x increases), it never touches the line. This means that the point 5 is excluded from the range.

Finally, we can see that above the horizontal line y=5, if we draw a horizontal line on the graph, it will touch the y axis. This means that every number greater than 5 is part of the range. Then, the set of numbers that represent the range is

(5,\text{infinity)}

4 0
1 year ago
32,000 oz = how many tons?
True [87]
1 ton, in the US, that is
5 0
3 years ago
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