All categories

2 years ago

Find the variation constant and an equation of variation for the given situation.

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

6 0

Answer:

$\displaystyle y=14\cdot x$

Step-by-step explanation:

<u>Directly Proportion</u>

It's said that y varies directly proportional as x, if:

$y=k\cdot x$

Where k is a constant of proportionality.

We know that y=7 when x=1/2.

Using the above condition, we can find the value of k:

$\displaystyle 7=k\cdot \frac{1}{2}$

Solving for k:

k=14

Thus, the equation is:

$\boxed{\displaystyle y=14\cdot x}$

You might be interested in

Can someone please tell me if these are correct?

iragen [17]

Number one is correct and so is two

3 0

3 years ago

Read 2 more answers

Using algebra, find the point at which the line k(x) = 5x - 1 intersects with the line h(x) = -3x - 1 ?

vichka [17]

The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)

Given: k(x) = 5x - 1, h(x) = -3x - 1

We need to find the point(if any) at which these two lines k and h meets.

To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.

Therefore, k(x) = h(x)

=> 5x - 1 = -3x - 1

=> 8x = 0

=> x = 0

k(x=0) = 5 * 0 - 1 = -1

Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)

Know more about "point of intersection" problems here: brainly.com/question/16929168

#SPJ1

8 0

1 year ago

How to solve and respond.

son4ous [18]

Step-by-step explanation:

the error:

it is stated that

$\frac{5x}{x+7} +\frac{7}{x} = \frac{5x}{x+7} +\frac{7(7)}{x+7}$

subtract (5x)/(x+7) from both sides

$\frac{7}{x} = \frac{7(7)}{x+7}$

multiply both sides by x + 7

7(x+7) = 49x

7x + 49 = 49x

subtract 7x from both sides to isolate x and its coefficient

49 = 42x

thus, this is only true when 49 = 42x. in order for these two equations to be equal, they must <em>always </em>be true, so this is wrong

the solution:

we want to express 7/x as (something) / (x+7). to do this, we can multiply 7/x by 1.

anything divided by itself = 1. thus, if we multiply both the numerator and the denominator by something that turns x into (x+7), we can do what we want to do.

(x+7)/x * x turns x into (x+7), so we multiply both the numerator and denominator by (x+7)/x to get

$\frac{7}{x} = \frac{7(x+7)/x}{x+7}$