Several ways to prove but let's use one only
Here
- PQ is the radius of circle Q
Also
- PQ is the radius of circle P
Hence P and Q circles have same radius
Now
As both are radius of circle Q
And
As both are radius of circle P.
Hence as per transitive property
Now
Hence
∆PQR is equilateral
X= -40
Thanks for letting me answer your question
Answer:
13 is x= 100 degrees
Step-by-step explanation:
-8 + k = -17
k = -17 + 8
k = 8 -17
k = -9
