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IRINA_888 [86]
3 years ago
5

An ellipse has a center at the origin, a vertex along the major axis at (10, 0), and a focus at (8, 0). Which equation represent

s this ellipse?

Mathematics
2 answers:
My name is Ann [436]3 years ago
6 0

Answer: A

Step-by-step explanation:

Alchen [17]3 years ago
3 0
Check the picture below.  So the ellipse looks more or less like so.

since the major axis is over the x-axis, is a horizontal ellipse, notice the "a" component length and the value for "c".

\bf \textit{ellipse, horizontal major axis}
\\\\
\cfrac{(x- h)^2}{ a^2}+\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a,  k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2- b ^2}
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=0\\
k=0\\
a=10\\
c=8
\end{cases}\implies 8=\sqrt{a^2-b^2}\implies 8^2=a^2-b^2\implies b^2=10^2-8^2
\\\\\\
b=\sqrt{100-64}\implies b=6
\\\\\\
\cfrac{(x-0)^2}{10^2}+\cfrac{(y-0)^2}{6^2}=1\implies \cfrac{x^2}{100}+\cfrac{y^2}{36}=1

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kobusy [5.1K]

The area of circle is 379.94 cm².

Step-by-step explanation:

Given,

Radius of circle = 11 centimeters

We have to calculate the area of circle.

We know that;

Area of circle = \pi r^2

Here;

π = 3.14 , r = 11

Area of circle = 3.14*(11)^2

Area of circle = 3.14*121

Area of circle = 379.94 squared centimeters

The area of circle is 379.94 squared centimeters.

Keywords: area, circle

Learn more about circles at:

  • brainly.com/question/11921476
  • brainly.com/question/1232765

#LearnwithBrainly

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A vertex of square is at(1,1) and its two parallel sides are y=x and y=x+1. find the equation of the remaining sides.Show your w
belka [17]

Answer:

\displaystyle y  =   - x  +  2

y =  - x  +1

Step-by-step explanation:

we are given a vertex of a square i.e <u>(</u><u>1</u><u>,</u><u>1</u><u>)</u>

and the equations of the two parallel sides

notice that, the given vertex coordinates satisfy one of the parallel side i.e <u>y=</u><u>x </u>which means that (1,1) points lie on one of Parallel sides

remember that,

every angles of a square is <u>9</u><u>0</u><u>°</u><u> </u>

therefore,

we need to figure out the remaining <u>Perpendicular</u><u> </u><u>line </u><u> </u>of the given Parallel sides so

let's figure out the perpendicular line of y=x line

recall that,

Parallel lines have the same slope thus

\displaystyle  m_{  \rm perpedicular} =  - 1

since we are given a vertex the equation of the perpendicular line should be

\displaystyle y - 1 =  - 1(x - 1)

distribute:

\displaystyle y - 1 =  - x  +  1

add 1 to both sides:

\displaystyle y  =   - x  +  2

to figure out the second perpendicular line we can consider the coordinates (0.5,0.5) of y=x equation

so the slope of the perpendicular line is -1

and the equation:

y - 0.5 =  - 1(x - 0.5)

distribute:

y - 0.5 =  - x  +0 .5

add 0.5 to both sides:

y =  - x  +1

and we are done!

4 0
3 years ago
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