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eimsori [14]
3 years ago
11

(03.06 MC)Luke filled the glasses shown below completely with water. The total amount of water that Luke poured into the glasses

is 90 cubic centimeters. What is the height of glass 1? Round your answer to the nearest hundredths. (Use π = 3.14.) Note that all measurements are in centimeters and images are not drawn to scale.
2.63 centimeters
3.82 centimeters
4.04 centimeters
5.62 centimeters

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Glass 1 is a right circular cylinder and Glass 2 is a cone. The total volume of water in both the glasses is 100 centimeters cubed. Some given dimensions are:

Right Circular Cylinder:

diameter = 5, thus radius is half of that, radius = cm

height = we need to find

(Note: Formula for volume, V, is )

Cone:

diameter = 6, thus radius is half of that, radius =  cm

height = 5.2 cm

(Note: Formula for volume, V, is )

Now adding the 2 volumes and equating to 100, and then solving for h will give us our answer (we will use π as 3.14). Let's do this.

pir^2+1/3pir^2h=100

(3.14)(2.5)^2h+1/3(3.14)(3)^2(5.2)=100

19.625h+48.984=100

19.625h=51.016

h=51.016/19.625=2.60 cm

Hence height of glass 1 is 2.60

2.63 cm

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Ganezh [65]

Answer:

(x + 1)² + (y - 1)² = 1.5625

Step-by-step explanation:

From the picture we see:

The radius is 5 units. Each unit is .25 so the radius is 1.25.

The centre or middle M= ( -1, 1 )

Circle with centre M and radius r :

(x - xM)² + (y - yM)² = r²

xM = -1

yM = 1

r = 1.25

(x - (-1))² + (y - 1)² = (1.25)²

(x + 1)² + (y - 1)² = 1.5625

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3 years ago
Please what is the interquartile range ?
AleksAgata [21]

Answer:

3.

Step-by-step explanation:

15 - 12 = 3.

The ends of the box are the lower and upper quartiles.

The difference  upper - lower = the interquartile range.

6 0
2 years ago
10m/
AlladinOne [14]

Answer:

Answer is D 312m^2

As  D= 8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

This makes triangle base of 6m

triangle side =8m

Rectangle side = 8m

and rectangle length = 11m

Step-by-step explanation:

First finding

A= 6 x 11 = 66m^2 (rectangle area) or 10 x 9 = 90sq^2

A = 1/2 x 6 x 11 = 33  (1/2bh) triangle

33+ 33 + 66 +66 + 66 = 264  or 33+ 33+ 90+90+90 =336

As 336 was not in the answer we do not know what 10m/9m represents, we then see this triangle prism is not a normal shape and its length is same as its height

a) is not in usual proportions.

We try again reversing which makes triangle sides 10m+ base 9m

= 1/2 x 10 x 10 = 50m^2 = triangle face area

we cannot continue the reverse as the triangle sides do not match the rectangle height. We therefore have to use the first answer C 264m^2

As 10m, 9m <do not match >6m 11m 8m

However if the given sizes 10m, 9m = bases of two different rectangles we would calculate 2 faces and add them each to one unknown face being one of the other face sizes we found to make 3.

10 x 8 = 80

9 x 8 = 72

To make one of these SA totals for rectangles alone

=80+80+72=232   or  72+72+80 =224

Then add to the 33 m^2 triangles

= 232+ 33+ 33 =297m^2

= 224+33+33 =310m^2

We can now determine that these measurements represent irregular values and are not answers within multiple choice, however d)  we can state the triangle is regular prism where triangle sides are regular too creating isosceles triangle 6,8,8,

8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

As we have ruled out rectangle with side 8m x 11m + A (33m^2) of triangle would equal 310m^2 (88+88+88+33+33) =330m

And ruled out rectangle with side 8m x 6m= 48m^2 (48+48+48+33+33 =210sqm)

So therefore if triangles were to equal 1/2 x 6 x 8 = 24

24 x 3= 72sqm

add the rectangle amounts above

= 72 + 88+ 88+ 88 =336^2

try another way and we find D. here below.

answer D= 72+ 80+80+80 = 312m^2 this can makes a correct answer D.

As last rule out is;

72 + 72 +72  (+triangle of 72) =288^2 would be irregular as this is equal to (9 x 8) x 3 and then the 11m is not used. It is also not a listed answer. Therefore;  D=312m^2 is correct.

A triangular prism has three rectangular sides and two triangular faces. To find the area of the rectangular sides, use the formula A = lw, where A = area, l = length, and h = height. To find the area of the triangular faces, use the formula A = 1/2bh, where A = area, b = base, and h = height.

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Answer:

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