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olga nikolaevna [1]
4 years ago
15

Simplify (2a^3) (5a^4)

Mathematics
2 answers:
Contact [7]4 years ago
8 0
(2a^3)(5a^4)
With this, you multiply the coefficients first, (2)(5)=10
Then when you multiply the variables, you add the exponents, (a^3)(a^4)=(a^(^3^+^4^))=a^7

So you would end up with: 10a^7
Leviafan [203]4 years ago
3 0

Answer: 10a^{7}

Step-by-step explanation: Think of this problem of having two parts. The coefficients 2 and 5 and the powers a^{4} and a^{7}. To multiply these two terms together, simply multiply their coefficients and we have to add the exponents because we are multiplying powers.

2 × 5 = 10

a^{3} × a^{7} = a^{10}

Therefore, our answer is 10a^{7}.

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Answer:

if they are similar then their sides are proportional and the following would be true:  

40/30 = 48/36  

reduce both sides:  

4/3 = 4/3  

so, yes, they are similar.

Step-by-step explanation:

6 0
3 years ago
An item has a listed price of $65 . If the sales tax rate is 3%, how much is the sales tax (in dollars)?
larisa86 [58]

Answer:

$1.95         hope this helped

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w
hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = \pi r^2h

V=3.14\times (0.5 m)^2\times 5 =3.925 m^3

Mass of gasoline = m

Density of gasoline = d = 673 kg/m^3

m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g .8 m/s^2

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

W =m\times g\times h

W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

6 0
3 years ago
Someone help pleaseeee
qaws [65]

Answer:

Part A = D

Part B = 5 and 50

Step-by-step explanation:

Part A:

area = 5*4x = 20x

so, 100 \leq 20x \leq  1000

Part B:

to leave it only by x, you divide both sides by 20

100/20 = 5, 1000/20 = 50

which 5\leq x\leq 50

7 0
3 years ago
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
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