1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
malfutka [58]
3 years ago
15

Manny buys four boxes of straws for his restaurant there are 500 straws in each box how many straws does he buy

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

2000 straws

Step-by-step explanation:

4 × 500 = 2000

You might be interested in
(No links please) I’ll mark Brainlyst
statuscvo [17]
18 bags of sand will be needed
3 0
3 years ago
What is 30 times 5/3? Also what is 24 times 5/3?
LUCKY_DIMON [66]

Answer:

30 times 5/3 is 50

24 times 5/3 is 40

5 0
4 years ago
Read 2 more answers
in a bag there are 6green balls4 blue balls and 5 yellow balls what is the probability of choosing a green ball ​
anyanavicka [17]

Answer:

50%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Factor the trinomial by grouping.<br> 9x^3 - 3x^2 -30x
katen-ka-za [31]

Answer:

3x(3x+5)(x-2)

Step-by-step explanation:

9x^3-3x^2-30x= \\\\3x(3x^2-x-10)= \\\\3x(3x^2+5x-6x-10)= \\\\3x(x(3x+5)-2(3x+5))= \\\\3x(3x+5)(x-2)

Hope this helps!

4 0
3 years ago
Use the box plots comparing the number of boy dogs and number of girl dogs attending doggy daycare each day for a month to answe
satela [25.4K]

The boxplots 1 and 2 represent the distribution of data using a five number summary for the male and the female attendance

<h3>(a) The IQR of the male's data</h3>

The first box plot represents the male's boxplot.

So, we have:

  • Upper quartile (Q3) = 14
  • Lower quartile (Q1) = 2

The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

<h3>(b) The difference in the median values</h3>

From the first and second boxplots, we have:

  • Median male = 10
  • Median female = 18

The difference (d) between these values is

d = 18 - 10

d = 8

So: the difference between the median values of each data set is 8

<h3>(c) The distribution of data</h3>

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

  • Male's data: presence of an outlier - use median
  • Female's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

<h3>(d) Reason for outliers</h3>

A possible reason for outliers is sampling problems

Read more about boxplots at:

brainly.com/question/26392028

#SPJ1

5 0
2 years ago
Read 2 more answers
Other questions:
  • Whats 245 over 320 simplified
    13·1 answer
  • 7 less than -2 times a number x is greater than or equal to 41 write a inequality for the statement above and find out a solutio
    15·1 answer
  • There are 472 stuffed beats in stock at a factory. The factory has 35 cartons of bears. There are 16 in a carton. How many more
    12·2 answers
  • A padlock has a four-digit code that includes digits from 0 to 9, inclusive. What is the probability that the code does not cons
    14·2 answers
  • The marks obtained by six boys in a test are 20,25,15,30,27 and 18. Find the mea
    6·2 answers
  • can this problem be solved using the unitary method?yes or no.An oven has a maximum temperature of 220°c.what will it be in 2 da
    15·1 answer
  • Divide.<br><br> −4 1/3÷−2 3/5<br><br><br> 1 2/3<br><br> 1 4/5<br><br> 2 1/5<br><br> 2 3/5
    13·1 answer
  • The cost of the toy is expressed by the function y = 3x + 5, where x is the number of toys. If Peter bought 8 toys, find the cos
    7·1 answer
  • Which number line could help you find the distance between (7,4) and (3,4)?
    14·1 answer
  • When asked to explain why there is no solution to |3x+7|-5 Jack said, "It is not a solution because the 5 is negative." Jack is
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!