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madreJ [45]
3 years ago
10

All the edges of a cube have the same length. Tony claims that the formula SA = 6s, where s is the length of

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0

Answer:

Here's what I get  

Step-by-step explanation:

a. Net of a cube

Fig. 1 is the net of a cube  

b. Does the formula work?

Tony's formula works if you ignore dimensions.

There are six squares in the net of a cube.

If each side has a unit length s, the total area of the cube is 6s.

c. Will the formula work for any rectangular prism?

No, because a rectangular prism has sides of three different lengths — l, w, and h — as in Fig. 2.

d. Area of a rectangular prism

A rectangular prism has six faces.

A top (T) and a bottom (b) — A = 2×l×w

A left (L) and a right (R)    —   A = 2×l×h

A front (F) and a back (B) —   A = 2×w×h

                                  Total area = 2lw + 2lh + 2wh

If l = 5 m, w = 6 m and h = 8 m,

\begin{array}{rl}A &=& \text{2$\times$ 5 m $\times$ 6 m + 2$\times$ 5 m $\times$ 8 m + 2 $\times$ 6 m $\times$ 8 m}\\&=& \text{60 m}^{2} + \text{80 m}^{2} + \text{96 m}^{2}\\&=& \textbf{236 m}^{2}\\\end{array}

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The price of gas on Wednesday was $2.03/gallon. On Friday, the price of gas was $2.26. What is the percent change in the price o
Vika [28.1K]

Answer:

Percent change in the price of gas is 9.85\%

Step-by-step explanation:

Percentage change equals the change in value divided by the absolute value of the original value, multiplied by 100 .

\text { Percentage Change }=\frac{\Delta V}{\left|V_{1}\right|} \times 100

Here

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The percent change in the price of gas

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Percent change in the price of gas is 9.85\%

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3 years ago
Find the derivative of the function <br> f(x) = √2^3 + ln(x^3) - 2x^3 - log_3(729) - 2/x^4
marysya [2.9K]

Applying the rules for the constant, logarithm and exponents, the derivative of the given function is of:

f'(x) = 3/x - 6x² - 8/(x^5).

<h3>What is the derivative of the function?</h3>

The function is given by:

f(x) = √2^3 + ln(x^3) - 2x^3 - log_3(729) - 2/x^4

The derivative of a sum is the sum of the derivatives, hence:

f'(x) = (√2^3)' + (ln(x^3))' - (2x^3)' - (log_3(729))' - (2/x^4)'

The derivative of a constant is of zero, hence:

  • (√2^3)' = 0.
  • (log_3(729))' = 0.

Hence:

f'(x) = (ln(x^3))' - (2x^3)' - (2/x^4)'.

The derivative of the logarithm is given by:

ln(h(x))' = (1/h(x)) x h'(x).

Hence:

(ln(x^3))' = 3x²/x³ = 3/x.

The derivative of the power of x is given by:

[x^n]' = nx^(n-1).

Hence:

  • (2x³)' = 6x².
  • (2/x^4)' = (2x^(-4))' = -8x^(-5) = -8/(x^5).

Hence the derivative of the function is given by:

f'(x) = 3/x - 6x² - 8/(x^5).

More can be learned about derivatives at brainly.com/question/23819325

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