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mariarad [96]
3 years ago
14

What is the slope of the line that contains the points (-1, 8) and (5,-4)?

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ;)

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3 years ago
Multiply. Answers should be in simplest form.<br> 3/7 x10
chubhunter [2.5K]

Answer:

4.28

I think this it. I used a calculator online to help solve this problem. I don't know what the answer is but I used an online calculator to solve the problem. I rounded the answer to the nearest hundreth.

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3 years ago
35 POINTS WILL MARK BRAINLIEST the area of a base of a square notepad is 9 square inches. What is the length of one side of the
zimovet [89]

Answer:

3

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area = l^2 = 9

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3 years ago
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Construct three parallel lines. Then construct two arbitrary non parallel transversal of the parallel lines. Make sure that the
zzz [600]

The image lines constructed are called parallel lines. They are parallel because  they are all equidistant to each other at every point and at no point between any of the lines will there be an intersection of the three lines.

<h3>What does it mean for two or more lines to be equidistant from each other?</h3>

Equidistance is simply another word for equal in distance. That is, parallel lines maintain equal distance from each other at all points along them.

See the attached construction as well as more insights about parallel lines from the link below.

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7 0
1 year ago
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
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