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4 years ago

Which table of values represents the residual plot?

Mathematics

1 answer:

pogonyaev4 years ago

7 0

Answer:

I see no tables but i do know that a residual value is the observed value minus the predicted value.

Basically take the predicted value and subtract it from the observed value.

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Solve this simultaneous equation using substitution method please explain how you got your answer i will mark you brainly if you

mylen [45]

The solution to the simultaneous equation is x = 1 and y = 3

<h3>How to solve simultaneous equation?</h3>

1 / 3 x + y = 10 / 3

2x + 1 / 4 y = 11 / 4

multiply equation one by 3 and multiply equation 2 by 4

Therefore,

x + 3y = 10

8x + y = 11

hence,

x + 3y = 10

24x + 3y = 33

23x = 23

x = 23 / 23

x = 1

Therefore,

1 + 3y = 10

3y = 10 - 1

3y = 9

y = 9 / 3

y = 3

learn more on equation here: brainly.com/question/10716108

#SPJ1

4 0

2 years ago

Can someone help me with a basic geometry question :c

viktelen [127]

480 I’m pretty sure ( a=LxWxH)

7 0

2 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at the

scZoUnD [109]

Answer:

$\frac{y}{x+y}$

Step-by-step explanation:

The required answer is the rate at which Machine A works when the two machines are combined.

Note: the rate of doing work is express as

$rate=\frac{1}{time taken} \\$

Hence we can conclude that Machine A working rate is

$machine A=\frac{1}{x} \\$ and machine B working rate is

$machine B=\frac{1}{y} \\$

When the two machine works together, the effective working rate is

$\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\$

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

$\frac{1}{x}*combine working rate$

$\frac{1}{x}*\frac{xy}{x+y}\\\frac{y}{x+y} \\$

Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is $\frac{y}{x+y} \\$

6 0

3 years ago

m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21

AnnZ [28]

The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!

6 0

3 years ago