Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Answer:
The amount driven would be 275, and the cost for both plans will be 77.75$
Step-by-step explanation:
make both equations
y=0.09x+53
y=0.13x+42
set them equal to each other and solve for x to get the distance
take that number and put it in one equation and solve for y to get the price of the plan for that value
A = 81 square in.
s = sqrt(A)
s = sqrt(81)
s = 9 in.
Answer:
$3 off which is $27
Step-by-step explanation:
10% of 30 is 3 so you would subtract 30 - 3
and you get $27
The answer is:
<span>y</span><span> > 2</span><span>x
</span>x<span> + 2</span>y<span> ≤ –8
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