Answer:
-10 is the correct answer to the given question .
Step-by-step explanation:
Missing information:
Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below
Triangle PQR has vertices 
It is translated according to the rule 
. What is the y-value of P'?
Now coming to the solution as already mention in the question
The translated rule is 
Now calculated the vertices P value according to the rule of translated
So -10 is the value of y in P vertices .
Answer:
Step-by-step explanation:
Two Angles are Supplementary when they add up to 180 degrees. They don't have to be next to each other, just so long as the total is 180 degrees. Examples: • 60° and 120° are supplementary angles.
D. 300 it is. is there more?
19. It notes or hints to using the quadratic formula because the equation can not be solved by factoring alone. Thus you must use the quadratic formula.
A=-16 B=25 C=3
It is so hard to type a normal equation let alone one of the quadratic formula so I will just attach a picture instead.
However you will end up getting two roots/zeros/x-intercepts of -0.11 and 1.67.
However since it is an application question asking for answers only in the first quadrant you must choose the positive x-intercept.
Therefore the water balloon will land at 1.67 seconds.
20. This question is very simple as it asks you to find a height at a given time. You simply put the given time (1second) into the equation and get your answer.
h=-16(1)^2+25(1)+3
h=12
Also don't mind my little scribble there. :)
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
