All categories

3 years ago

Sketch the figure: Two different isosceles triangles with perimeter 4a + b

Mathematics

1 answer:

Nikitich [7]3 years ago

3 0

The two triangles with the given perimeter is attached .

Perimeter is the sum of all sides.

For the first triangle , sies are 2a,2a and b.

So the perimeter is

$Perimeter = 2a+2a+b
\\
Perimeter = 4a+b$

For the second triangle, sides are a,a, and 2a+b. Therefore perimeter is

$Perimeter = a+ a + 2a+b
\\
Perimeter = 4a+b$

So for both triangles, perimeter is

$4a+b$

You might be interested in

A store sells 6 bananas for $4. Determine how much it would cost to buy 15 bananas

Archy [21]

Answer:

$10

Step-by-step explanation:

Since 6 cost four dollars 3 would cost 2 dollars multiply 3 to get 15 bananas and 2 to get $10

8 0

3 years ago

Read 2 more answers

Can you help me solve for x

astraxan [27]

X=2 I believe but I need to keep typing to make it longer

3 0

2 years ago

Help please and thank you

stiks02 [169]

First, we can see that there are four sides, and none of these equation contradict each other, so it is safe to say that this is a quadrilateral.

Second, all of the equations have the slope of 0 or undefined, so it is a rectangle.

Lastly, the four points of intersection shows us that the side lengths are 3 and 5 units, so the area of it is 15 units².

7 0

3 years ago

Read 2 more answers

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

30 years ago

Zoe was 2/3 as old as Luke

18 years ago

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

30 years ago

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

18 years ago

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0

10 months ago

At 106°F, a certain insect chirps at a rate of 67 times per minute, and at 108°F, they chirp 83 times per minute. Write an equat

Step2247 [10]

Answer:

$y=8x-781$

Here, $x$ represents temperature and $y$ denotes rate of chirping per minute.

Step-by-step explanation:

Let $x$ represents temperature and $y$ denotes rate of chirping per minute.

At $106$ °F, a certain insect chirps at a rate of $67$ times per minute.

Take $(x_1,y_1)=(106,67)$

At $108$ °F, they chirp $83$ times per minute.

Take $(x_2,y_2)=(108,83)$

Slope intercept form:

$y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{16}{2})(x-106)\\\\y-67=8(x-106)\\y-67=8x-848\\y=8x+67-848\\y=8x-781$

3 0

3 years ago