Question

Sketch the figure: Two different isosceles triangles with perimeter 4a + b

Answer 1

The two triangles with the given perimeter is attached .

Perimeter is the sum of all sides.

For the first triangle , sies are  2a,2a and b.

So the perimeter is

$Perimeter = 2a+2a+b \\ Perimeter = 4a+b$

For the second triangle, sides are a,a, and 2a+b. Therefore perimeter is

$Perimeter = a+ a + 2a+b \\ Perimeter = 4a+b$

So for both triangles, perimeter is

$4a+b$