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Tamiku [17]
3 years ago
7

A cone has a volume of 1570 cubic inches. Which of the following gives the volume of a cylinder with the same radius and same he

ight as the cone?
A.4710
B.3140
C.523.3
Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

The volume of the cylinder is 4710 cubic inches

Step-by-step explanation:

Volume of the cone = 1570 cubic inches

Volume of cone = 1/3(volume of the cylinder)

So,

Volume of the cylinder = 3(volume of the cone)

Volume of the cylinder = 3(1570)

= 4710 cubic inches

The volume of the cylinder is 4710 cubic inches

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Determine how far the vehicle travels in 3 hours.
Karo-lina-s [1.5K]

Answer:

360 miles

Step-by-step explanation:

The unit rate here is (240 miles) / (2 hours), or 120 mph.

In 3 hours the vehicle travels (120 mph)(3 hrs) = 360 miles

8 0
3 years ago
Can someone help me really please
JulsSmile [24]

Answer:

26

Step-by-step explanation:

Let x represent the missing number

8\frac{11}{15} = 7\frac{x}{15}

Convert both fractions to improper fractions

\frac{131}{15} = \frac{105 + x}{15}

Cross multiply

15(105 + x) = 15(131)

1,575 + 15x = 1,965

Subtract both sides by 1,575

15x = 1,965 - 1,575

15x = 390

Divide both sides by 15

x = \frac{390}{15}

x = 26

4 0
3 years ago
How do you solve for X ax-x=c
MArishka [77]
Factor out the "x"  and you'll have:
x(a-1) =c \qquad /:(a-1) \\ x=\frac{c}{a-1} \qquad \qquad  a\neq 1
8 0
3 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
I need help with these two problems.
Dennis_Churaev [7]

Answer:

the equation is - y=x

Explanation:

Given -

y=x+4

We have to find a line passing through the point (2,2) nd parallel to the given line.

Find the slope of the given line.

It is the coefficeint of x

m₁ = 1

The two lines are parallel. Hence

m₂=m₁=1 Where m₂is the slope of the second line.

You have slope and the points (2,2)

Find the Y intercept

y=mx+c\\2=(1)(2)+C\\2=2+C\\C=2-2=0

Y-Intercept C=0 and slope m₂=1

Fix the equation

y=x

8 0
2 years ago
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