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Tresset [83]
3 years ago
9

How do I convert these improper fractions to mixed numbers: 29/4, 13/6, 73/9, 65/8, 17/2, 5/2, 25/4, 43/7, 29/4, 73/9, 19/3, 43/

7, 11/5, 91/10 and 37/6
Mathematics
2 answers:
slava [35]3 years ago
5 0
Divide the numerator by the denominator 
use the answer as the whole number
use the remainder as the numerator
keep the deniminator

the answers: 
7  1/4
2   1/6
8  1/8
8  1/2
2  1/2
6  1/4
6  1/7
7  1/4 (same question)
8  1/8 (same question)
6  1/3
2  1/5
9  1/10
6  1/6

GenaCL600 [577]3 years ago
5 0
Just think if you had a mixed number and your trying to turn it into an improper fraction, two and 1 fourth, take the two and the four and add it together, than times it by one and you have your improper fraction, just turn it around and do the same thing, if u do not get it, just tell me in a private conversation
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Answer:

Step-by-step explanation:

answer: 4 hours

8 0
2 years ago
Find the least common multiple of: 12x^3y^2 and 15x^2y^5
allochka39001 [22]

Answer: 60x^3y^5

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: 12x^3y^2 and 15x^2y^5.

Since, 12x^3y^2=2\times2\times3\times x^3y^2

15x^2y^5=3\times5\times x^2y^5

The least common multiple of: 12x^3y^2 and 15x^2y^5. = 2\times2\times3\times5\times x^3y^5=60x^3y^5 [take highest power of x and y ]

Hence, the least common multiple of: 12x^3y^2 and 15x^2y^5. = 60x^3y^5

3 0
3 years ago
What divides into 78?? Thanks for your help if your trying to solve it <3
Mademuasel [1]
6 divides into 78 which gives a quotient of 13.
Hope i'm the brainliest!
5 0
2 years ago
Simplify – 2(7x – 3)
ANTONII [103]

All you need to do here is multiply the outside number by both 7x and -3.

When done correctly it should look like this:

-14x+6

Thats the answer.

7 times 2 gives you 14 but when multiplying mixed signs it turns negative so it would be -14.

negative 3 times negative 2 gives you 6. Both signs are negative, and you would suppose it would turn into a negative but thats only true when both signs are mixed. Both the 3 and the 2 are negative, making the signs the samez giving you positive

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5 0
2 years ago
Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

    For x = a,

    f(a) = 8a²

    Now substitute these values in the expression,

    \frac{f(x)-f(a)}{x-a} = \frac{8x^2-8a^2}{x-a}

                  = \frac{8(x^2-a^2)}{(x-a)}

                  = \frac{8(x-a)(x+a)}{(x-a)}

                  = 8(x + a)

b). \frac{f(x+h)-f(x)}{h} = \frac{8(x+h)^2-8x^2}{h}

                      = \frac{8(x^2+h^2+2xh)-8x^2}{h}

                      = \frac{8x^2+8h^2+16xh-8x^2}{h}

                      = (8h + 16x)

                      = 8(h + 2x)

4 0
3 years ago
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