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3 years ago

Would really appreciate it if someone could help!! Have been stuck on the question alll day !

Mathematics

1 answer:

aksik [14]3 years ago

3 0

The answer would be:
ABD=78.8
DBC=61.1

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Can you hlep me hhhhhh

hram777 [196]

Answer:

The answer is 8 please Brainlist me

Step-by-step explanation:

6^2+h^2=10^2

36+h^2=100

Solving for h gives 8

4 0

2 years ago

Read 2 more answers

Which of the following Roots would be between 8 and 7

azamat

To find which of the following roots is between "8" and "7" we can calculate the root of which numbers result in 8 and 7. To do this we will power them by 2, this is done because power is the oposite operation to the root. Doing this gives us:

$\begin{gathered} 8^2=64 \\ 7^2=49 \end{gathered}$

So the root of 64 is 8 and the root of 49 is 7. We need to find the number that is between 49 and 64.

From the options the only one that qualifies is 52. The correct option is b.

3 0

1 year ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

alicia and her friends Brittany, Kenji and Ellis are taking a pottery class. The four friends have to share 3 blocks of clay. Ho

ki77a [65]

You need to divide the 3 blocks of clay by the 4 friends. 3 goes in the dividend and the 4 is outside. 3 divided by 4 is equal to 0.75 or 3/4, so each friend gets 0.75 or 3/4 clay

7 0

3 years ago

Find ordered pairs: choose two of the answers below

Anarel [89]

Answer:

b -3,3 c 6,9 hope this helps

5 0

2 years ago