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Alex787 [66]
3 years ago
5

Two similar cylinders have heights of 3 cm and 6 cm respectively. If the volume of the smaller cylinder is 30 cm3, find the volu

me of the larger cylinder.Required to answer. Single line text.​
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

Volume of big cylinder = 1,438.76 cm (Approx.)

Step-by-step explanation:

Given:

Height of smaller cylinder = 3 cm

Height of big cylinder = 6 cm

Volume of smaller cylinder = 30 cm³

Find:

Volume of big cylinder

Computation:

Volume of smaller cylinder = πr²h

(22/7)(r²)(3) = 30

Radius of small cylinder = 1.783 cm (Approx.)

So,

Radius of big cylinder = 1.783 x 2 = 3.566 cm (Approx.)

Volume of big cylinder = πr²h

Volume of big cylinder = (22/7)(3.566)²(6)

Volume of big cylinder = 1,438.76 cm (Approx.)

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Candice won the lottery for 30000 dollars.However 20% of her money has to go to the state for taxes.How much money will she rece
Trava [24]

Answer:

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Step-by-step explanation:

This question can be solved using a rule of three.

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$30000 - 1

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7 0
3 years ago
Find x so that the points (x,x+1), (x+2,x+3) and (x+3,2x+4) form a right-angled triangle.
azamat

Let <em>a</em>, <em>b</em>, and <em>c</em> be vectors each starting at the origin and terminating at the points (<em>x</em>, <em>x</em> + 1), (<em>x</em> + 2, <em>x</em> + 3), and (<em>x</em> + 3, 2<em>x</em> + 4), respectively.

Then the vectors <em>a</em> - <em>b</em>, <em>a</em> - <em>c</em>, and <em>b</em> - <em>c</em> are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(<em>a</em> - <em>b</em>) • (<em>a</em> - <em>c</em>) = 0

<em>or</em>

(<em>a</em> - <em>b</em>) • (<em>b</em> - <em>c</em>) = 0

<em>or</em>

(<em>a</em> - <em>c</em>) • (<em>b</em> - <em>c</em>) = 0

We have

<em>a</em> - <em>b</em> = (<em>x</em>, <em>x</em> + 1) - (<em>x</em> + 2, <em>x</em> + 3) = (-2, -2)

<em>a</em> - <em>c</em> = (<em>x</em>, <em>x</em> + 1) - (<em>x</em> + 3, 2<em>x</em> + 4) = (-3, -<em>x</em> - 3)

<em>b</em> - <em>c</em> = (<em>x</em> + 2, <em>x</em> + 3) - (<em>x</em> + 3, 2<em>x</em> + 4) = (-1, -<em>x</em> - 1)

Case 1: If (<em>a</em> - <em>b</em>) • (<em>a</em> - <em>c</em>) = 0, then

(-2, -2) • (-3, -<em>x</em> - 3) = (-2)×(-3) + (-2)×(-<em>x</em> - 3) = 2<em>x</em> + 12 = 0   ==>   <em>x</em> = -6

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Case 2: If (<em>a</em> - <em>b</em>) • (<em>b</em> - <em>c</em>) = 0, then

(-2, -2) • (-1, -<em>x</em> - 1) = (-2)×(-1) + (-2)×(-<em>x</em> - 1) = 2<em>x</em> + 4 = 0   ==>   <em>x</em> = -2

which would make <em>a</em> - <em>c</em> = (-3, -1) and <em>b</em> = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (<em>a</em> - <em>c</em>) • (<em>b</em> - <em>c</em>) = 0, then

(-3, -<em>x</em> - 3) • (-1, -<em>x</em> - 1) = (-3)×(-1) + (-<em>x</em> - 3)×(-<em>x</em> - 1) = <em>x</em> ² + 4<em>x</em> + 6 = 0

but the solutions to <em>x</em> here are non-real, so we throw out this case.

So there are two possible values of <em>x</em> that make a right triangle, <em>x</em> = -6 and <em>x</em> = -2.

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3 years ago
Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

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Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of GT and EF

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Finally, we can use the Pythagorean Theorem to find the length of AG:

AG^{2} + GT^{2} = AT^{2}

AG^{2} + 8^{2} = 10^{2}

AG^{2} + 64 = 100

AG^{2} = 36

AG = 6

8 0
2 years ago
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