1st is 1 1/2 2nd is 2 and 3 is 2
Answer:
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Step-by-step explanation:
The given question is :
8 = 4 * 2
32 = 16 * 2
![\sqrt{8} =\sqrt{4*2} = 2\sqrt{2} \\\sqrt{32} =\sqrt{16*2} =4\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B8%7D%20%3D%5Csqrt%7B4%2A2%7D%20%3D%202%5Csqrt%7B2%7D%20%5C%5C%5Csqrt%7B32%7D%20%3D%5Csqrt%7B16%2A2%7D%20%3D4%5Csqrt%7B2%7D)
∴
=
=
Is this the question of when will they have to buy all 3 items again
Answer:
4.979044478499338 × 10²⁶
Step-by-step explanation:
Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.
Combination factorial is define by ⁿCr = ![\frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
21 group of mice receiving Drug A can be selected in ⁶⁰C₂₁ = ![\frac{60!}{21!39!}](https://tex.z-dn.net/?f=%5Cfrac%7B60%21%7D%7B21%2139%21%7D)
(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug
Drug B 21 mice can be chosen with ³⁹C₂₁ = ![\frac{39!}{21!18!}](https://tex.z-dn.net/?f=%5Cfrac%7B39%21%7D%7B21%2118%21%7D)
( 39 - 21 = 18) remained for control with ¹⁸C₁₈ =
The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ =
×
×
= 4.979044478499338 × 10²⁶
To find the total add the two numbers together:
593 + 352 = $945