It would have to be 3 because distance can't be a negative number.
Combine like terms you would get 4c=48 then divide it by 4 you'll get c=12
Answer:
2.108*10^3
Step-by-step explanation:
Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴
≅ 736.2 to the nearest tenth foot