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worty [1.4K]
3 years ago
14

Negative thirty-one less than s is greater than 93

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

s > 62

Step-by-step explanation:

  1. Write it out: s - (-31) > 93
  2. Simplify: s + 31 > 93
  3. Subtract 31 from each side, so it now looks like this: s > 62

I hope this helps!

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X+3y=28 when x =28 find the value for y plz help
Lisa [10]

Answer:

y = 0

Step-by-step explanation:

Plug in 28 for x. Solve for the equation:

x + 3y = 28

(28) + 3y = 28

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 28 from both sides:

28 (-28) + 3y = 28 (-28)

3y = 0

Isolate the variable, y. Divide 3 from both sides:

(3y)/3 = (0)/3

y = 0

y = 0 is your answer.

~

4 0
4 years ago
I need help with this question fast. I’m running out of time!
ale4655 [162]
No idea ı m sorry lkddkdk
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4 years ago
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Find the inverse of the given function.<br><br> f(x) = -1/2√x + 3, x ≥ -3
inna [77]
<span>Find the inverse of the given function.

f(x) = -1/2√x + 3, x ≥ -3

I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3.  If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.

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4.  Replace "y" with 

           -1
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Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers.  The domain here is (-infinity,3]
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kykrilka [37]

The given expression is

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And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2

And a function is undefined when denominator is zero. And at x=-6, denominator become zero.

So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .

4 0
4 years ago
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I think its A once again i THINK its A sorry if im wrong 
 
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