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3 years ago

What is the mean and mode of the data set shown below? {2, 4, 5, 6, 8, 2, 5, 6}

1 answer:

4 0

The average is calculated by adding all numbers and dividing by the count:

(2+4+5+6+8+2+5+6)/8 = 38/8 = 4.75

The mode is the number that occurs most often, however, this is the case for 2, 5 and 6. A data set can have multiple modes. 2, 5 and 6 are modes.

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Please solve it and show a graph

vichka [17]

Answer: There is no photo it's just a black screen

Step-by-step explanation:

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3 years ago

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A car travels along a straight stretch of road. It proceeds for 16.2 mi at 57 mi/h, then 24.6 mi at 44 mi/h, and finally 45.1 mi

LekaFEV [45]

Answer:

The average velocity the entire trip was 43.25 mi/h

Step-by-step explanation:

In this case we have to calculate an average based on the miles traveled. First we have to calculate the total of miles traveled, then calculate the portion of the total travel of each and with this calculate the average speed during the trip. First the total miles traveled:

$TotalMiles=16.2+24.6+45.1=85.9$

Now the percentages:

At 57 mi/h were $\frac{16.2}{85.9}=0.19$

At 44 mi/h were $\frac{24.6}{85.9}=0.29$

At 37.8 mi/h were $\frac{45.1}{85.9}=0.52$

Now multiplying the speed by the portion and summing them we can have the average velocity:

$57*0.19+44*0.29+37.8*0.52=43.25$

The average velocity the entire trip was 43.25 mi/h

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3 years ago

A $20, 000 brand new car depreciate its value every year following the pattern, $16,000, $12,800, $10,240. How much will the car

seropon [69]

Answer:

Step-by-step explanation:

Use the info given in the exponential equation to find the value of b, the rate of decay.

$v(t)=a(b)^t$ where v(t) is the value of the car after a certain number of years, t, have gone by, a is the initial value, and b is the rate of decay. We have everything we need but b:

a = 20000

v(t) = 16000 after t = 1 year:

$16000=20000(b)^1$ so

b = .8 Taken in context, this means that the car depreciates 20% each year. Now we can solve the problem being asked of us, which is to find the value of the car after t = 5 years:

$v(t)=20000(.8)^5$ which simplifies down a bit to

v(t) = 20000(.32768) so

v(t) = 6553.60, choice C.

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3 years ago

Select all that apply please

Digiron [165]

Answer:

i think it's x=0 and 0=1

6 0

3 years ago

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7. If you run a half marathon (21 km) in 2 hours 6 minutes, how much tirne does it take you to run one kilometre?

kupik [55]

Answer:

6 minutes per kilometer

Step-by-step explanation:

[] First, let's get one unit. I will be using minutes;

2 hours 6 minutes = 120 mintues + 6 mintues = 126 mintues

[] There are about 21 kilometers in a half-marathon;

126 minutes / 21 kilometers = 6 minutes per kilometer

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

8 0

3 years ago