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fenix001 [56]
3 years ago
8

A chain saw requires 5 hours of assembly and a wood chipper 4 hours. A maximum of 40 hours of assembly time is available. The pr

ofit is $150 on a chain saw and $230 on a chipper. How many of each should be assembled for maximum​ profit?
Mathematics
1 answer:
iris [78.8K]3 years ago
8 0
So first you need to by the chain saw and the chipper for $380. It should only take you about 9 hours to assemble it. And lets say that the 31 hours you were looking for the best of the best chain saw and chipper.
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Can someone please help me??
Semmy [17]

since we don't know any of your vocabulary, I might not be using the ones you learned


since we have points A and B and points F(A) and F(B), I think they want us to use the word 'translation'

"The function F(x) translates each point to the right without moving them up or down." would be my description


also the 2 lines are paralell


7 0
3 years ago
Create an equation with one solution of x = −4.
katen-ka-za [31]

Answer:

What is missing is -5x - 20

Step-by-step explanation:

To find this, simply solve for the parenthesis as if it were a variable of its own. This will allow you to see exactly what is missing.

8x - (x - 20) = 2x - (_______)

8x - x + 20 = 2x - (_______)

7x + 20 = 2x - (_______)

5x + 20 = - (_______)

-5x - 20 = (_______)

So the answer for the parenthesis is -5x - 20

3 0
3 years ago
What do you see in this picture??(My younger brother's drawing)​
lubasha [3.4K]

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I see a fish writing on paper

7 0
3 years ago
Read 2 more answers
Suppose Jessica opens a savings account with $5000 that compounds interest daily. The APR at the time Jessica opens the account
IrinaK [193]
Hi there

1+0.035=(1+r/360)^360
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6 0
3 years ago
Find the indicated limit, if it exists.
Paha777 [63]
The limit is the y value that the graph approaches from both sides as x approaches the target limit

it they approach different values from the left and right sides, the limit does not exist

we want to find the limit as x approaches 5

we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5

evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0

f(5)=8

f(x)=x+3
f(5)=5+3
f(5)=8

it approaches 0 and 8 from both sides
the limit doesn't exist
D
8 0
3 years ago
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