Ask question

Ask question

All categories

3 years ago

8

A chain saw requires 5 hours of assembly and a wood chipper 4 hours. A maximum of 40 hours of assembly time is available. The pr

ofit is $150 on a chain saw and $230 on a chipper. How many of each should be assembled for maximum profit?

1 answer:

iris [78.8K]3 years ago

8 0

So first you need to by the chain saw and the chipper for $380. It should only take you about 9 hours to assemble it. And lets say that the 31 hours you were looking for the best of the best chain saw and chipper.

You might be interested in

Write an algebraic expression to model the given context. Give your answer in simplest form. the price p of a coat reduced by a

satela [25.4K]

Answer:

We conclude that the expression of the price p of a coat reduced by a 5% discount will be: 0.95 p

Step-by-step explanation:

Let 'p' be the original price

Discount = 5% = 0.05

The discount amount can be calculated by multiplying the original price by 5% or 0.05

Discount Amount = 5% × p

= 0.05 × p

= 0.05 p

Given that the price p of a coat reduced by a 5% discount.

Thus, the price after 5% discount can be calculated by subtracting the discount amount i.e. 0.05 p from the original price p.

Thus,

The expression of the price p after 5% discount = p - 0.05 p

= 0.95 p

Therefore, we conclude that the expression of the price p of a coat reduced by a 5% discount will be: 0.95 p

3 0

3 years ago

Each sister in the Johnson family owns one of these fish tanks. Each tank is shaped like a rectangular prism. They want to combi

Vilka [71]

Answer:

B.)536 $cm^{3}$

Step-by-step explanation:

Find the volume of all the fish tanks.

Green fish tank...

4 x 9 x 6 = 216

Brownish fish tank...

4 x 4 x 8 = 128

Orange Fish tank...

6 x 4 x 8 = 192

Since we are COMBINING the fish tanks, we add the volumes.

216 + 128 + 192 = 536

536 $cm^{3}$

Hope this helped! Please mark as brainlies! Thanks!

7 0

4 years ago

Which point identifies the intersection of two lines with slopes that multiply to −1?

Sever21 [200]

Answer:

Perpendicular lines are lines that intersect at right angles. If you multiply the slopes of two perpendicular lines in the plane, you get −1 . That is, the slopes of perpendicular lines are opposite reciprocals .

Hope this help:)

3 0

3 years ago

Which answer is the approximate standard deviation of the data set?

Ierofanga [76]

Answer: A. 6.5

Step-by-step explanation:

Here, the given set = { 15, 19 3, 12, 17, 2, 2, 8}

Mean, $\overline{ x} = \frac{15+19+3+12+17+2+2+8}{8} = \frac{78}{8} = 9.75$

Number of elements, n = 8

$\frac{\sum (|x-\overline{x}|)^2}{n}=42.4375$

Thus, the standard deviation, $\sigma =\frac{\sqrt{\sum(|x-\overline{x}|)^2} }{n}=\sqrt{\frac{339.5}{8}}=\sqrt{42.4375} = 6.51440711\approx 6.5$

⇒ Option A is correct.

4 0

3 years ago

Read 2 more answers

A professor knows that her statistics students' final exam scores have a mean of 79 and a standard deviation of 11.3. In his cla

OverLord2011 [107]

For each student, there are only two possible outcomes. Either they score an A, or they do not. The probability of a student scoring an A is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Additionally, to find the proportion of students who scored an A, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Proportion of students that scored an A:

Scores have a mean of 79 and a standard deviation of 11.3, which means that $\mu = 79, \sigma = 11.3$

Scores of 90 or higher are graded an A, which means that the proportion is 1 subtracted by the p-value of Z when X = 90, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 79}{11.3}$

$Z = 0.97$

$Z = 0.97$ has a p-value of 0.8340.

1 - 0.8340 = 0.166

The proportion of students that scored an A is 0.166.

Probability that 6 students or more will score an "A" on the final exam:

Binomial distribution.

22 students, which means that $n = 22$

The proportion of students that scored an A is 0.166, which means that $p = 0.166$

The probability is:

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{22,0}.(0.166)^{0}.(0.834)^{22} = 0.0184$

$P(X = 1) = C_{22,1}.(0.166)^{1}.(0.834)^{21} = 0.0807$

$P(X = 2) = C_{22,2}.(0.166)^{2}.(0.834)^{20} = 0.1687$

$P(X = 3) = C_{22,3}.(0.166)^{3}.(0.834)^{19} = 0.2239$

$P(X = 4) = C_{22,4}.(0.166)^{4}.(0.834)^{18} = 0.2117$

$P(X = 5) = C_{22,5}.(0.166)^{5}.(0.834)^{17} = 0.1517$

Then

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0184 + 0.0807 + 0.1687 + 0.2239 + 0.2117 + 0.1517 = 0.8551$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8551 = 0.1449$

Thus

0.1449 = 14.49% probability that 6 students or more will score an "A" on the final exam.

For a problem that used the normal distribution, you can check brainly.com/question/15181104, and for a problem that used the binomial distribution, you can check brainly.com/question/15557838

3 0

3 years ago