A)
s = sweater
j = jeans
Equations:
4s + 2j = 140
2s + 3j = 150
B)
4s + 2j = 140
2s + 3j = 150
Multiply (-2) to the second equation
-2 (2s + 3j = 150)
-4s - 6j = -300
Now you have the equations:
4s + 2j = 140
-4s - 6j = -300
-----------------------------add
-4j = -160
j = 40
4s + 2(40) = 140
4s + 80 = 140
4s = 60
s = 15
The cost for a sweater is $15 and the cost for a jean is $40
We used the elimination method to solve the system of equations.
C)
Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85
Total cost for 1 pair of jeans and 3 sweaters = $85
If she has $225 the
$225 / $85 = 2.64
2 jeans = 2 x 40 = $80
6 sweaters = 6 x $15 = $90
So She can only buy 2 jeans and 6 sweaters
1. X + 5
2.15-15
3. C= ( 3x9.95)+(2x14.98)
4.?
5. 12,000+500x ?idk
1.3n (it can be simplified like any other equation just add like terms and remember there is a one before every variable)
In probability 2 events are independent if the occurrence of 1 event does not affect the occurrence of the other event. Mathematically, if event A and event B are independent, then 
. For our two events in this problem we have that 
and 
. If these two events are independent, then we should have that,
.A and B are independent events if the probability of A and B is 0.1
Answer:
0.125....................
