F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
Answer: D) -5/6 < -3/5 < -4/7 < -4/9
Step-by-step explanation:
Since putting fractions from least to greatest by using negatives the number or fraction has to be closed to 0. -5/6 is the farthest from 0 so it'll be the least -4/9 is closes to 0 so -4/9 is the most.
Answer:
6
Step-by-step explanation:
Answer:
x=ln(72)/ln(12) or x=1.721
Step-by-step explanation:
