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8_murik_8 [283]
3 years ago
10

How to do this question plz?​

Mathematics
1 answer:
True [87]3 years ago
3 0

Answer:

Ratio of George age to Carl's age to Alex age = 1 : 12 : 4

Step-by-step explanation:

Let the age of Alex = A years

Age of George = G years

And age of Carl = C years

"Alex is 12 years older than George"

A = G + 12 ------(1)

"Carl is 3 times older than Alex"

C = 3A

C = 3(G + 12)

C = 3G + 36 ------(2)

"Sum of their ages is 68 years"

A + G + C = 68 ------(3)

By substituting the values of A and G in equation (3)

G + 12 + G + 3G + 36 = 68

5G + 48 = 68

5G = 20

G = 4 years

From equation (1),

A = 4 + 12 = 16 years

From equation

C = 3(4) + 36

C = 12 + 36

C = 48 years

Ratio of their ages = G : C : A

                               = 4 : 48 : 16

                               = 1 : 12 : 4

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Add 5 to me.Then divide by 7.If you add 12 and the subtract 7,you get 10
qaws [65]

Answer: 30

Step-by-step explanation:

Let the number be y

Add 5 to me

Y+5............equ1

Divide by 7

Y+5/7

Add 12

Y+5/7+12

Subtract 7

(Y+5)/7+(12-7)=10

12-7=5

Substitute

(Y+5)/7+5=10

Find the lowest common multiple

((Y+5)+7(5))/7=10

(Y+5)+35)/7=10

Cross multiply

Y+5+35=70

Y+40=70

Y=70-40

Y=30

The unknown number is 30

6 0
3 years ago
State restrictions on the variable.
Mandarinka [93]
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7 0
3 years ago
April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R&B CDs. What is t
padilas [110]
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7 0
4 years ago
Read 2 more answers
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
Does this seem answer seem correct?
Blababa [14]
I mean I think so I’m not completely sure it’s a really hard question
5 0
3 years ago
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