Answer: 30
Step-by-step explanation:
Let the number be y
Add 5 to me
Y+5............equ1
Divide by 7
Y+5/7
Add 12
Y+5/7+12
Subtract 7
(Y+5)/7+(12-7)=10
12-7=5
Substitute
(Y+5)/7+5=10
Find the lowest common multiple
((Y+5)+7(5))/7=10
(Y+5)+35)/7=10
Cross multiply
Y+5+35=70
Y+40=70
Y=70-40
Y=30
The unknown number is 30
There's one unforgivable taboo that transcends just about every branch of mathematics, and that's dividing by zero. Division by zero is undefined, so any fraction with a zero in its denominator is by definition absurd. For what values of x would the denominators on either of those fractions be zero? Those will define the restrictions on your variable.
The answer is B: <span>choosing five CDs where not all of them are pop</span>
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
I mean I think so I’m not completely sure it’s a really hard question