C. 4x + y = 21
4(3) + 9 = 21
12 + 9 = 21
21 = 21
The answer is 5.83
Use the Pythagorean Theorem to calculate the 3rd side length.
a^2+b^2=c^2
3^2+5^2=c^2
Answer:
2log(3) + log(x) + 2log(y) + 5log(z)
Hope this helps(:
Step-by-step explanation:
Answer: 25/676
Step-by-step explanation:
Number of possible outcomes = 26
In other to win, one must draw must be either (A, E, I, O or U)
Therefore required drws to win = 5
First draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Second draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Therefore,
P(winning twice) = (5/26) × (5/26) = 25/676
