4 years ago

In △PQR, find the measure of ∡P.

2 answers:

8 0

57.6² = 33.8² + QR²
QR² = 2.175,32
QR = 46.64

57.6/sen90º = 46.64/sen(P)
sen(P) = 46.64*sen90º/57.6
sen(P) = 0.809
angle P is sen^-1 = 54.06º ≈ 54.1º

Maksim231197 [3]4 years ago

7 0

Answer:

54.1º

Step-by-step explanation:

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