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rjkz [21]
2 years ago
9

Which equation models the area of the geometric figure, below. Select all that apply:

Mathematics
2 answers:
Nadya [2.5K]2 years ago
8 0

Answer:

20x+50......

and 10(2x+5)

mash [69]2 years ago
8 0

Answer:

  • 20x+59
  • 10(2x+5)

Step-by-step explanation:

<h2>Mark as brainliest... </h2>
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Bob is 35 and susan is 30 years old, find the ratio of his age to hers_____
ivanzaharov [21]
The ratio is 35:30
This can simplifies by dividing by 5

=35/5:30/5
= 7:6 is the answer
7 0
2 years ago
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Find the value of x ​
Karo-lina-s [1.5K]

Answer:

x = 68°

Step-by-step explanation:

∠ DCB = ∠ EDC = 27° ( alternate angles )

Thus ∠  ECB = 23° + 27° = 50°

The sum of the 3 angles in a triangle = 180°, thus

x = 180° - (62 + 50)° = 180° - 112° = 68°

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2 years ago
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Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
20 points <br><br> What do you remember about types of angles?
Allushta [10]

An acute angle is one that measures LESS than 90˚

An obtuse angle is one that measures between 90˚ and 180˚

A reflex angle is an angle that measures between 180˚ and 360˚

There are other many types of angles such as alternate angles and corresponding angles, but those 3 are the main ones.

Have a great day <3

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2 years ago
2. Your bank account has -15 in it. You deposit $7 per day.
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2.a it should have 20 dollars in it
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