To solve this problem we will apply the concept related to the electric field defined from the laws of Coulomb. For this purpose we will remember that the electric field is equivalent to the product of the Coulomb constant due to the change of the charge over the squared distance, mathematically this is
Here,
k = Coulomb's constant
r = Distance from center of terminal to point where electric field is to found
q = Excess charge placed on the center of terminal of Van de Graff's generator
Replacing we have that,
Therefore the electric field is
Work is force x displacement
So force is 48 and displacement is 5.2 as given
Therefore 48 x 5.2
Which is 249.6
Approximately 250 J (joules)
Answer:
I would probably say C to be completely honest
Explanation:
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Answer: Question 10: I believe the answer is C, hope this helps!
Explanation: