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Natalija [7]
3 years ago
8

Select the correct answer.

Physics
1 answer:
Triss [41]3 years ago
5 0

Answer:

Jim's kinetic energy is 54.67 J.

Explanation:

Given that,

Mass, m = 15 kg

Velocity, V = 2.7 m/s

We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 15\ kg\times (2.7\ m/s)^2

E = 54.67 J

So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.

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If you used 16 gallons when driving 367 miles, what was your gas mileage over that distance
White raven [17]
Your gas mileage would be 22.93 miles per gallon.
6 0
3 years ago
A Bullet Off mass 100 gm is fired From A Gun Off mass 5 Kg. If the backward velocity of the gun's 5 m / s, what is forward veloc
Elena L [17]

Answer:

250 m/s

Explanation:

The mass of the bullet, m₁ = 100 g = 0.1 kg

The mass of the gun, m₂ = 5 kg

The backward velocity of the gun, v₂ = -5 m/s

Given that the momentum is conserved, we have;

The total initial momentum = The total final momentum

The gun and the bullet are at rest, therefore, we have;

The initial momentum = 0

The total final momentum = m₁·v₁ + m₂·v₂

Where;

v₁ = The forward velocity of the bullet

Therefore, we get;

m₁·v₁ + m₂·v₂ = 0

0.1 kg × v₁ + 5 kg × (-5 m/s) = 0

0.1 kg × v₁ = 5 kg × 5 m/s

v₁ = (5 kg × 5 m/s)/(0.1 kg) = 250 m/s

The forward velocity of the bullet, v₁ = 250 m/s

6 0
3 years ago
Which statement correctly explains mechanical advantage?
Shtirlitz [24]
I'm not entirely sure but I would think it's A.
4 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Orlov [11]

Answer:

I dont know this but I have an app for you if your really strangling

Explanation:

its called Qanda. it really good and teachers help you a lot

8 0
3 years ago
You have a stopped pipe of adjustable length close to a taut 62.0 cmcm, 7.25 gg wire under a tension of 4710 NN. You want to adj
Oksana_A [137]

Answer:

6 cm long

Explanation:

F = 4110N

Vo(speed of sound) = 344m/s

Mass = 7.25g = 0.00725kg

L = 62.0cm = 0.62m

Speed of a wave in string is

V = √(F / μ)

V = speed of the wave

F = force of tension acting on the string

μ = mass per unit density

F(n) = n (v / 2L)

L = string length

μ = mass / length

μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

V = √(F / μ)

V = √(4110 / 0.0117)

v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

F(n) = n * (v / 2L)

F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

The frequency for standing wave in a stopped pipe

f = n (v / 4L)

Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

4L = 0.2399

L = 0.0599

L = 0.06cm

L = 6cm

The pipe should be 6 cm long

6 0
3 years ago
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