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Helga [31]
3 years ago
8

What formula do I use for the second question? For number 3 how is one energy converted to the other? ( using arrows ) I get num

ber 4 so I don't need help with that!

Physics
1 answer:
Fed [463]3 years ago
6 0
<u>#2</u>
Use the formula ... Kinetic energy = (1/2) x (mass) x (speed)²

<u>#3 - a).</u>
sun => energy travels as electromagnetic waves => reaches Earth as
         heat & light energy.

sun => absorbed in plants => eaten by animals => animals die =>
       decay into oil in millions of years => we burn the oil to get the energy.

<u>#3 - b).</u>
food I ate for lunch => metabolized into glucose by my body
       => some of it burned in my muscles to generate energy for immediate needs
       => the rest of it stored as fat for future needs.

<u>#3 - c).</u>
flower pot rolls off the ledge => gravity does work on it all the way down,
       producing the kinetic energy it has when it hits the floor.

<u>#3 - d).</u>
oil or natural gas is burned, releasing heat energy => energy is used
       to generate electricity => electricity flows through cables from the
       power generating plant to your home => hot plate plugged into the
       wall => turns electrical energy back into heat energy => heat energy
       is conducted into the bottom of the beaker, flows through the glass
       to the inside surface => heat energy is conducted from the inside of
       the glass to the water, which gets hotter as it absorbs more energy. 
=============================

<u>Note:</u>
#1 on the sheet is wrong.
"Work = force x distance"  that's correct
But 25-kg is the <em>mass</em> of the ball, <em>not </em>the gravitational <em>force </em>on it.
The force on it is (mass) x (gravity), called its "weight".
   That's (25-kg) x (9.8 m/s²) = 245 kg-m/s² = 245 newtons .
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ehidna [41]

Answer:

The speed at the bottom of the driveway is3.67m/s.

Explanation:

Height,h= 5sin20°= 1.71m

Potential energy PE=mgh= 2000×9.8×1.71

PE= 33516J

KE= PE- Fk ×d

0.5mv^2= 33516 - (4000×5)

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5 0
3 years ago
A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the
Digiron [165]

Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

W_{r} = |F_{r}|*|d|*cos(\theta_{1})

Where:                

F_{r}: is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

W_{g} = |F_{g}|*|d|*cos(\theta_{2})  

The force of gravity is given by the weight of the bike.

F_{g} = -mgsin(24)     

And the angle between the force of gravity and the direction of motion is 180°.

W_{g} = |mgsin(24)|*|d|*cos(\theta_{2})  

W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J  

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.  

I hope it helps you!                                                                                          

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Answer:

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Explanation:

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