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maxonik [38]
3 years ago
7

PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

Solution:

Given point is (2, –5).

slope of the line m = -\frac{2}{3}

Here, x_1=2, y_1=-5

Equation of a line passing through the point:

y-y_1=m(x-x_1)

$y-(-5)=-\frac{2}{3} (x-(-5))

$y+5=-\frac{2}{3} (x+5)

$y+5=-\frac{2}{3} x-\frac{10}{3}

Subtract 15 from both sides of the equation.

$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5

$y=-\frac{2}{3} x-\frac{25}{3}

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

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---------------------------------------------------------

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