Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice 
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above 
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485 
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
 
        
             
        
        
        
Answer:
1)B
2)C
3)B
4)A
5)C
Step-by-step explanation:
BrainLiest please
 
        
                    
             
        
        
        
Answer 
1/2 and -4/3
Step-by-step explanation:
 
        
             
        
        
        
Answer:
I resolve the expression
(4x+3) (3x-8)=12x2-32x+9x-24
12x2-23x-24
the polynomial (4x+3) (3x-8) is equivalent a the expression 12x2-23x-24
 
        
             
        
        
        
Answer:
5q I would say
Step-by-step explanation:
As 
3
x
−
q
=
5
q
 , adding 
=
q
 on both sides, we get
3
x
−
q
+
q
=
5
q
+
q
 
or 
3
x
=
6
q
 , now multiplying both sides by 
1
3
 , we get
3
x
×
1
3
=
2
6
q
×
1
3
 
or 
x
=
2
q