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3 years ago

A certain drug is made from only two ingredients: compound A and compound B. There are

Mathematics

1 answer:

NISA [10]3 years ago

3 0

Answer:

425 milliliters of compound A are needed

Step-by-step explanation:

We were told that $5$ milliliters of compound A and $6$ milliliters of compound B is needed to make the drug.

This means that each drug contains 11 milliliters of both compounds.

$\frac{935}{11}=85$ milliliters is the volume of each drug.

Therefore the chemist needed $5\times 85=425$ millilirteres of compound A.

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Answer:

$\frac{1}{2}$ cups of flour

Step-by-step explanation:

Substitute 1 in for m.

$f=\frac{1}{2}(1)$

Simplify.

$f=\frac{1}{2}$

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2 years ago

You earned $62,715 this year and your Income tax calculator says you owe $8,818 in taxes. But you neglected to deduct $1,000 for

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Step-by-step explanation:

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3 years ago

How do you simplify ( 11-7)+3 using order of operations?

alex41 [277]

I think this is

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3 years ago

Read 2 more answers

Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

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2 years ago

Write down the integer values satisfied by this diagram. I n -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9

Flauer [41]

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. The integer values that satisfy the given diagram are 0, 1, 2, and, 3.

<h3>What is a number line?</h3>

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. It’s not a ruler, so the space between each number doesn’t matter, but the numbers included on the line determine how it’s meant to be used.

Given a solid dot at 3, while an open dot at -1, also, there is a line from -1 to 3. Therefore, the integer values that satisfy the given diagram are 0, 1, 2, and, 3.

Learn more about the Number line:

brainly.com/question/557284

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2 years ago