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Svet_ta [14]
3 years ago
6

A mutual fund manager must decide how much money to invest in Atlantic Oil (A) and how much to invest in Pacific Oil (P). At lea

st 60% of the money invested in the two oil companies must be in Pacific Oil. A correct modeling of this constraint is
Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer:

\frac{P}{A+P}\geqslant 0.6

Step-by-step explanation:

Amount of money to invest in Atlantic Oil= A

Amount of money to invest in Pacific Oil = P

Total money invested in the two oil companies = A+P

Since at least 60% of the money invested in the two oil companies must be in Pacific Oil

\frac{P}{A+P} \times 100\geqslant 60

\Rightarrow \frac{P}{A+P} \geqslant \frac{60}{100}

\Rightarrow \frac{P}{A+P}\geqslant 0.6

Hence the required model is \frac{P}{A+P}\geqslant 0.6

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x=1, x=4

Step-by-step explanation:

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Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
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It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

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3 years ago
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Find all the solutions to the equation 7sin^2x -14sinx+2=-5
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I will get you started.

Let sin x = u

Then 7sin^2x -14sinx+2=-5 become

7u^2 - 14u = - 5

7u^2 - 14u + 5 = 0

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7 0
3 years ago
Yo please help
Alex Ar [27]

Answer:

Options 1, 3 and 4 are true

Step-by-step explanation:

The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,

DE^2=EF^2+DF^2\\ \\DE^2=24^2+7^2\\ \\DE^2=576+49\\ \\DE^2=625\\ \\DE=25\ units

Find trigonometric functions:

\sin \angle D=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\cos \angle E=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\tan \angle D=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}=\dfrac{EF}{DF}=\dfrac{24}{7}

\sin \angle E=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{DF}{DE}=\dfrac{7}{25}

Thus, options 1, 3 and 4 are true

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