Step-by-step explanation:
∫₋₂² (f(x) + 6) dx
Split the integral:
∫₋₂² f(x) dx + ∫₋₂² 6 dx
Graphically, if f(-x) = -f(x), then ∫₋₂² f(x) dx = 0. But we can also show this algebraically.
Split the first integral:
∫₋₂⁰ f(x) dx + ∫₀² f(x) dx + ∫₋₂² 6 dx
Using substitution, write the first integral in terms of -x.
∫₂⁰ f(-x) d(-x) + ∫₀² f(x) dx + ∫₋₂² 6 dx
-∫₂⁰ f(-x) dx + ∫₀² f(x) dx + ∫₋₂² 6 dx
Flip the limits and multiply by -1.
∫₀² f(-x) dx + ∫₀² f(x) dx + ∫₋₂² 6 dx
Rewrite f(-x) as -f(x).
∫₀² -f(x) dx + ∫₀² f(x) dx + ∫₋₂² 6 dx
-∫₀² f(x) dx + ∫₀² f(x) dx + ∫₋₂² 6 dx
The integrals cancel out:
∫₋₂² 6 dx
Evaluating:
6x |₋₂²
6 (2 − (-2))
24
Answer:
<u>1/4</u>
Step-by-step explanation:
if you take the fraction 3/12 and divide it by 3 on both sides, you get the remaining fraction 1/4
Answer:
End result is ln(-x) + 1
Step-by-step explanation:
1, ln x + 2
2. ln(x + 2) + 2
3. ln(x + 2 - 2) + 2 = ln x + 2
4. ln x + 1
5. ln(-x) + 1
The degree of the polynomial function f is the number of zeros function f has.
The remaining zeros of the polynomial function are -i, 4 + i and 2 - i
<h3>How to determine the remaining zeros</h3>
The degrees of the polynomial is given as;
Degree = 6
The zeros are given as:
i, 4-i,2+i
The above numbers are complex numbers.
This means that, their conjugates are also zeros of the polynomial
Their conjugates are -i, 4 + i and 2 - i
Hence, the remaining zeros of the polynomial function are -i, 4 + i and 2 - i
Read more about polynomials at:
brainly.com/question/4142886
Answer:
The last one.
Step-by-step explanation:
