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Assoli18 [71]
4 years ago
12

The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13. b. Identify the time interv

als during which the acceleration of the shuttle bus is constant. c. Find the value for the average velocity of the shuttle bus during each time interval identified in b. d. Find the acceleration of the shuttle bus during each time interval identified in b.
Mathematics
1 answer:
elena-14-01-66 [18.8K]4 years ago
7 0
Since the Figure is not given let me answer the items above by concept. 
(b) The intervals during which the acceleration of the bus is constant is the portion where the graph is a line that is neither horizontal or vertical. 

(c) The area bounded by the curve and the x-axis is the distance. To get the average velocity, determine the total distance and divide by the total time interval.
 
(d) The acceleration is determined by calculating the differences between velocities and dividing this difference by the difference of time interval.
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Sam lives 8 miles from work and Mike lives 30 miles from work. How much farther is Mike’s trip to work than Sam’s?
telo118 [61]
22 miles,
30miles - 8 miles = 22 miles
Mikes trip to work is 22 miles farther than sam’s
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3 years ago
One of the legs of a right triangle measures 17 cm and the other leg measures 5 cm. Find the measure of the hypotenuse. If neces
Semenov [28]

Answer:

17.7 cm^2

Step-by-step explanation:

The formula for finding the hypotenuse using the pythagorean theorem is:

a^{2}+b^{2}=c^{2}

or, it can also be c=\sqrt{a^2+b^2}. But I will be using the first formula.

We first plug in the "legs" to the equation:

a^{2} =17^{2} \\b^{2}=5^2

17^2+5^2=c^2\\17^2+5^2=314

Now, you find the square root of 314.

\sqrt{314}=17.72^2

And finally, just round to the nearest tenths place!

17.7^2

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2 years ago
Rosa had 592 stickers. She gave 212 stickers to Meg.
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Answer: I need help with this as fast as someone can. PLS let me know who to do it

Step-by-step explanation:

4 0
3 years ago
Hector and Francis spent a total of $47.50 at the mall. If Hector spent 50% more than Francis, how much did Francis spend at the
AveGali [126]
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6 0
3 years ago
Maja manages a community garden which has rectangular garden plots that are 15 ft by 10 ft. She wants to add a uniform path arou
tiny-mole [99]

The path should be 6.38 feet wide

Let x be the width of the path.

Since the rectangular plot has an area with dimensions 15 ft by 10 ft, we add x to each dimension to give the dimensions of the rectangular plot plus uniform path.

So, the dimensions are 15 + x by 10 + x respectively.

So, the area of the rectangular plot plus uniform path is A

A = (15 + x)(10 + x)

Since the combined area of the path is 350 square feet, A = 350 ft²

So, (15 + x)(10 + x) = 350

Expanding the brackets, we have

150 + 15x + 10x + x² = 350

x² + 25x + 150 = 350

x² + 25x + 150 - 350 = 0

x² + 25x - 200 = 0

Using the quadratic formula, we find x, the width of the path

So,

x = \frac{-25 +/-\sqrt{25^{2} - 4X1 X (-200)} }{2 X1 } \\x = \frac{-25 +/-\sqrt{625 + 800)} }{2}\\x = \frac{-25 +/-\sqrt{1425} }{2}\\x = \frac{-25 +/-37.75 }{2}\\x = \frac{-25 + 37.75 }{2} or x = \frac{-25 - 37.75 }{2}\\x = \frac{12.75 }{2} or x = \frac{-62.75 }{2}\\x = 6.375 or x = -31.375

Since x cannot be negative, we choose the positive answer.

x = 6.375 ft

x ≅ 6.38 ft

So, the path should be 6.38 feet wide

Learn more about width of a path here:

brainly.com/question/15382035

5 0
3 years ago
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