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Assoli18 [71]
3 years ago
12

The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13. b. Identify the time interv

als during which the acceleration of the shuttle bus is constant. c. Find the value for the average velocity of the shuttle bus during each time interval identified in b. d. Find the acceleration of the shuttle bus during each time interval identified in b.
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0
Since the Figure is not given let me answer the items above by concept. 
(b) The intervals during which the acceleration of the bus is constant is the portion where the graph is a line that is neither horizontal or vertical. 

(c) The area bounded by the curve and the x-axis is the distance. To get the average velocity, determine the total distance and divide by the total time interval.
 
(d) The acceleration is determined by calculating the differences between velocities and dividing this difference by the difference of time interval.
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Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%
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Answer:

In the account that paid 6% Susan invest \$6,000

In the account that paid 5% Susan invest \$4,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

t=1\ years\\ P=\$x\\r=0.06

substitute in the formula above

I1=x(0.06*1)

I1=0.06x

Part b) account that paid 5% simple interest per year

in this problem we have

t=1\ years\\ P=\$10,000-\$x\\r=0.05

substitute in the formula above

I2=(10,000-x)(0.05*1)

I2=500-0.05x

we know that

I1+I2=\$560

substitute and solve for x

0.06x+500-0.05x=560

0.01x=560-500

0.01x=60

x=\$6.000

therefore

In the account that paid 6% Susan invest \$6,000

In the account that paid 5% Susan invest \$4,000

6 0
3 years ago
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