What is 3 1/3

A toy store is having a sale. A video game system has an original price of $99. It is on sale for 40% off the original price. Fi

stira [4]

Answer:

The price would now be $59.40

Step-by-step explanation:

4 0

3 years ago

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A glass paperweight is shown below.

sasho [114]

Answer:

$A=190.75\ cm^2$

Step-by-step explanation:

The diameter of a hemisphere, d = 9 cm

Radius, r = 4.5 cm

We need to find the surface area of the paperweight. The formula for the surface area of a hemisphere is given by :

$A=3\pi r^2\\\\A=3\times 3.14\times (4.5)^2\\\\A=190.75\ cm^2$

So, the surface area of the paperweight is $190.75\ cm^2$ .

3 0

3 years ago

Write an equation for the trend line shown. Type answer in y = mx + b format.

grandymaker [24]

Answer:

y=1/4x+250

Step-by-step explanation:

6 0

3 years ago

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Easy 6th grade math

Grace [21]

Answer:

18 in

Step-by-step explanation:

3 0

3 years ago

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Consider a sample with a mean of 30 and a standard deviation of 5. Use Chebyshev's theorem to determine the minimum percentage o

Ainat [17]

Answer:

a) We are within 2 deviations from the mean since 30 -2*5 = 20 and 30 + 2*5 = 40. So our value for k = 2 and we can find the % like this:

$\% = (1- \frac{1}{2^2}) *100 = 75\%$

b) We are within 3 deviations from the mean since 30 -3*5 = 20 and 30 + 3*5 = 45. So our value for k = 3 and we can find the % like this:

$\% = (1- \frac{1}{3^2}) *100 = 88.88\% \approx 89\%$

c) We are within 1.4 deviations from the mean since 30 -1.4*5 = 23 and 30 + 1.4*5 = 37. So our value for k = 1.4 and we can find the % like this:

$\% = (1- \frac{1}{1.4^2}) *100 = 48.97\% \approx 49\%$

d) We are within 2.6 deviations from the mean since 30 -2.6*5 = 17 and 30 + 2.6*5 = 43. So our value for k = 2.6 and we can find the % like this:

$\% = (1- \frac{1}{2.6^2}) *100 = 85.2\% \approx 85\%$

e) We are within 3.4 deviations from the mean since 30 -3.4*5 =13 and 30 + 3.4*5 = 47. So our value for k = 3.4 and we can find the % like this:

$\% = (1- \frac{1}{3.4^2}) *100 = 91.35\% \approx 91\%$

Step-by-step explanation:

For this case we need to remember what says the Chebysev theorem, and it says that we have at least $1-\frac{1}{k^2}$ of the data liying within k deviations from the mean on the interval $\bar X \pm k s$

We know that $\bar X= 30, s=5$

Part a

For this case we want the values between 20 and 40

So we are within 2 deviations from the mean since 30 -2*5 = 20 and 30 + 2*5 = 40. So our value for k = 2 and we can find the % like this:

$\% = (1- \frac{1}{2^2}) *100 = 75\%$

Part b

For this case we want the values between 15 and 45

So we are within 3 deviations from the mean since 30 -3*5 = 20 and 30 + 3*5 = 45. So our value for k = 3 and we can find the % like this:

$\% = (1- \frac{1}{3^2}) *100 = 88.88\% \approx 89\%$

Part c

For this case we want the values between 23 and 37

So we are within 1.4 deviations from the mean since 30 -1.4*5 = 23 and 30 + 1.4*5 = 37. So our value for k = 1.4 and we can find the % like this:

$\% = (1- \frac{1}{1.4^2}) *100 = 48.97\% \approx 49\%$

Part d

For this case we want the values between 17 and 43

So we are within 2.6 deviations from the mean since 30 -2.6*5 = 17 and 30 + 2.6*5 = 43. So our value for k = 2.6 and we can find the % like this:

$\% = (1- \frac{1}{2.6^2}) *100 = 85.2\% \approx 85\%$

Part e

For this case we want the values between 13 and 47

So we are within 3.4 deviations from the mean since 30 -3.4*5 =13 and 30 + 3.4*5 = 47. So our value for k = 3.4 and we can find the % like this:

$\% = (1- \frac{1}{3.4^2}) *100 = 91.35\% \approx 91\%$

8 0

3 years ago

What is 3 1/3 - 1 1/2​

What is 3 1/3 - 1 1/2